这是我的情景：
a = ["","","","","","","","","",""] #10 elements. Need not always be blank.
b = ["a","b","c","d"]
我想修改a，使n的第一个a元素替换为b的元素n = b.size()：
a = ["a","b","c","d","","","","","",""]
那么，是否有像a.replace(b)这样简单的东西减去截断？
另一种方法是将a.size() - b.size()个元素追加到b。
答案 0 :(得分：2)
您可以使用切片：
a[0, 4] = b
或动态长度：
a[0, b.length] = b