Question

所以我现在已经在Android应用程序上工作了一段时间。一切顺利，直到我在Android 2.2以上的设备上测试此代码。

我只是在AsyncTask中将数据发布到我的PHP服务器，它只是永远不会完成，没有任何错误。我试图设置超时但无济于事。我将每个不同的语句放在try {} catch {}块中，但它们都没有触发。通过在互联网上阅读，似乎错误是在HTTPClient.execute（httppost）序列中的某个地方。这是我的代码：

private class NewUserTask extends AsyncTask<Context, Void, String> {

    @Override
    protected String doInBackground(Context... params) {

        Functions functions = new Functions();
        if (!functions.isOnline(params[0])) {
            return "false";
        }

        String result = null;
        InputStream is = null;
        StringBuilder sb = null;

        String userDeviceID = Secure.getString(params[0].getContentResolver(),Secure.ANDROID_ID);
        String userAccount = getUsername(params[0]);

        HttpClient httpclient = null;
        try {
            HttpParams httpParameters = new BasicHttpParams();
            HttpConnectionParams.setConnectionTimeout(httpParameters, 3000);
            HttpConnectionParams.setSoTimeout(httpParameters, 5000);

            httpclient = new DefaultHttpClient(httpParameters);
        }catch (Exception e) {
            return "error httpclient setup";
        }

        String url = null;
        try {
            url = "http://www.xxx.com/xxx/xxx.php?userDeviceID=" + userDeviceID + "&database=" + "xxx" + "&userAccount=" + userAccount;
        }catch (Exception e) {
            return "url setup";
        }


        HttpPost httppost = null;
        try {
            httppost = new HttpPost(url);
        }catch (Exception e) {
            return "httppostsetup";
        }

        try {
            httppost.setEntity(new UrlEncodedFormEntity(new ArrayList()));
        }catch (Exception e) {
            return "setetnityfsda";
        }

        HttpResponse response = null;
        try {
            response = httpclient.execute(httppost);
        }catch (Exception e) {
            return "response";
        }

        try {
            is = response.getEntity().getContent();
        }catch (Exception e) {
            return "getcontent";
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"));
            sb = new StringBuilder();
            sb.append(reader.readLine() + "\n");
            String line = "0";

            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }

            is.close();
            String temp = sb.toString();
            temp = temp.substring(0, temp.length() - 1);
            result = temp;

        }catch (Exception e) {
            return "error in reader";
        }

        return result;
    }


    protected void onPostExecute(String result) {
        Functions functions = new Functions();

        functions.showMessage("Info", result, DisplayExtrasActivity.this);
    }

    private String getUsername(Context context){
        Pattern emailPattern = Patterns.EMAIL_ADDRESS; // API level 8+
        Account[] accounts = AccountManager.get(context).getAccounts();
        for (Account account : accounts) {
            if (emailPattern.matcher(account.name).matches()) {
                return account.name;
            }
        }

        return null;
    }
}

然后我称之为：

new NewUserTask().execute(DisplayExtrasActivity.this);

我真的希望有人能够帮助我，因为我几乎无望。我已经花了几个小时来解决这个问题，试图找出我出错的地方。

编辑：更多代码！

HTTP Post永远不会响应（冻结）SDK 2.2之上

0 个答案: