Question

我很清楚这是一个在更简单的情况下有明确解决方案的问题，但我已经实现了一些我认为不这样做的东西或者由于这个问题完全改变它是错误的，也许有一些我看不到的东西。好吧，我有客户，每个客户都有任务，每个任务都有代理人分配给它。我想将所有这些加载到一个对象，并根据我从我的客户端获得的一些搜索对象查询这些参数，就像这样。

public IEnumerable<object> GetMissionsBySearch(MissionSearchCriteria search, int loggedUserId)
    {
        var today = DateTime.Now.AddHours(12);
       try
        {
            var query = from mission in context.Missions.Include("AssignedAgents")
                join client in context.Clients on mission.ClientId equals client.Id
                select new
                    {
                        mission,
                        client.Name,
                        client.Office,
                        client.Id,
                    }
                into x
                select x;

            if (search.ByType != ActivityType.All)
            {
                query = query.Where(s => s.mission.ActivityType == search.ByType);
            }
            if (search.IsTakenCareOf != "all")
            {
                bool endedOrNot;
                bool value = Boolean.TryParse(search.IsTakenCareOf, out endedOrNot);
                if (value)
                {
                    query = query.Where(s => s.mission.TakenCareOf == endedOrNot);    
                }

            }
            if (search.ByCreator == ByCreator.Me)
            {
                query = query.Where(s => s.mission.AddedbyUserId == loggedUserId
                    && s.mission.AssignedAgents.Count(a => a.Id == loggedUserId) > 0);
            }
            if (search.ByCreator == ByCreator.Other)
            {
                query = query.Where(s => s.mission.AddedbyUserId != loggedUserId 
                    && s.mission.AssignedAgents.Count(a => a.Id == loggedUserId) > 0);
            }
            if (search.ByCreator == ByCreator.Both)
            {
                //query = query.Where(s => s.mission.AddedbyUserId == loggedUserId
                //   || s.mission.AssignedAgents.Count(a => a.Id == loggedUserId) > 0);
                //query = query.Where(s => s.mission.AddedbyUserId != loggedUserId
                //   && s.mission.AssignedAgents.Count(a => a.Id == loggedUserId) > 0);
            }
            if (search.ByDate == ByDate.All)
            {
                //Doing Nothing
            }
            if (search.ByDate == ByDate.Today)
            {
                query = query.Where(s=> s.mission.Deadline.Value <= today);
            }
            else if (search.ByDate == ByDate.Yesterday)
            {

                var yesterday = DateTime.Now.AddHours(-24);
                query = query.Where(s => s.mission.Deadline > yesterday
                    && s.mission.Deadline < today);
            }
            else if (search.ByDate == ByDate.LastWeek)
            {
                var lastweek = DateTime.Now.AddDays(-8);
                query = query.Where(s => s.mission.Deadline > lastweek
                    && s.mission.Deadline < today);
            }
            else if (search.ByDate == ByDate.ByDays && search.Days > 0)
            {
                var daysBack = DateTime.Now.AddDays(search.Days*-1);
                query = query.Where(s => s.mission.Deadline > daysBack);
            }
            else if (search.ByDate == ByDate.BetweenDates)
            {
                query = query.Where(s => s.mission.Deadline > search.FromDate && s.mission.Deadline < search.ToDate);
            }
            else if (search.ByDate == ByDate.EveryThingBackToDate)
            {
                query = query.Where(s =>  s.mission.Deadline < search.ToDate);
            }              
            return query.ToList();

我阅读了这三篇文章但仍未成功实现这一目标， Entity Framework & Include http://blogs.msdn.com/b/alexj/archive/2009/06/02/tip-22-how-to-make-include-really-include.aspx http://itsharpau.wordpress.com/2011/09/30/entity-framework-4-query-with-include-doesnt-work-with-join/

请帮忙，谢谢。

Answer 1

如果你投射到（匿名或命名）类型，

Include永远不会有效。想一想，哪个类应该EF包含子集合？

如果你这样做，那么包含就可以了

var query = from mission in context.Missions.Include("AssignedAgents")
    join client in context.Clients on mission.ClientId equals client.Id
    select mission

然后EF将拥有Mission个对象，可以加载AssignedAgents个集合。

如果您不想获得完整的对象，可以通过将AssignedAgents作为匿名类型的属性合并来获得相同的效果：

var query = from mission in context.Missions
    join client in context.Clients on mission.ClientId equals client.Id
    select new
        {
            mission,
            client.Name,
            client.Office,
            client.Id,
            Agents = mission.AssignedAgents
        };

EF6包括加入不包括。

1 个答案: