Question

我拿到了那张桌子：

id    table_id      ....
1         1
2         1
3         1
4         2
5         2

我想要一个查询来获取所有拥有相同table_id的最佳记录

结果：

id    table_id      ....
1         1
4         2

我试过了：

SELECT        
   id, shift_id, name_of_shift, person_in_shift, 
   starttime_in_shift, endtime_in_shift, table_id, 
   startdate, enddate, point_id
FROM            
   sarcshifttable
WHERE        
   (table_id IN (SELECT DISTINCT table_id
                 FROM sarcshifttable AS sarcshifttable_1))

但它带给我所有的数据，我只想要顶一个

Answer 1

SELECT * FROM Table
  WHERE ID IN
    (SELECT ID FROM ( SELECT MIN(ID)as ID,table_id FROM Table GROUP BY table_id)x)

Answer 2

他说他希望所有的专栏都回来了，所以必须这样：

SELECT        
   id, shift_id, name_of_shift, person_in_shift, 
   starttime_in_shift, endtime_in_shift, table_id, 
   startdate, enddate, point_id
FROM            
   sarcshifttable
WHERE id IN 
(
 SELECT MIN(id)
 FROM sarcshifttable
 GROUP BY table_id
)

Answer 3

他们是对的 - 通过table_id选择最低（MIN()）ID分组，您可以找到该特定表ID的最早行。

这样的事情：

SELECT
  MIN(id), table_id
FROM
  table1
GROUP BY
  table_id

<强>更新更好地理解请求，以下SQL将起作用：

SELECT
  id, shift_id, name_of_shift, person_in_shift, 
   starttime_in_shift, endtime_in_shift, table_id, 
   startdate, enddate, point_id
FROM
  table1
WHERE
  id IN (
    SELECT MIN(ID)
    FROM table1 GROUP BY table_id
  )

A working example (updated) can be seen here at SQLFiddle。

Answer 4

DECLARE @What TABLE
(
    id INT,
    tableId INT
)

INSERT INTO @What
VALUES
(1, 1),
(2, 1),
(3, 1),
(4, 2),
(5, 2)

SELECT a.id, a.tableId
FROM
(   
    SELECT id, tableId, Rank() OVER (PARTITION BY tableId ORDER BY id) localRank
    FROM @What
) a
WHERE a.localRank = 1
ORDER BY  a.id

id tableId

1 1

4 2

选择具有共享列的值SQL Server的顶级记录

4 个答案: