Question

假设你有以下数组：

$nodes = array(
    "parent node",
    "parent node",
    array(
        "child node",
        "child node",
        array(
            "grand child node",
            "grand child node")));

您将如何将其转换为XML字符串，使其看起来像：

<node>
    <node>parent node</node>
    <node>parent node</node>
    <node>
        <node>child node</node>
        <node>child node</node>
        <node>
            <node>grand child node</node>
            <node>grand child node</node>
        </node>
    </node>
</node>

一种方法是通过递归方法，如：

function traverse($nodes)
{
    echo "<node>";

    foreach($nodes as $node)
    {
        if(is_array($node))
        {
            traverse($node);
        }
        else
        {
            echo "<node>$node</node>";
        }
    }

    echo "</node>";
}

traverse($nodes);

我正在寻找一种使用迭代的方法。

Answer 1

您可以使用Iterator迭代数组，然后生成所需的输出：

class TranformArrayIterator extends RecursiveIteratorIterator
{
    protected function indent()
    {
        echo str_repeat("\t", $this->getDepth());
        return $this;
    }
    public function beginIteration()
    {
        echo '<nodes>', PHP_EOL;
    }
    public function endIteration()
    {
        echo '</nodes>', PHP_EOL;
    }
    public function beginChildren()
    {
        $this->indent()->beginIteration();
    }
    public function endChildren()
    {
        $this->indent()->endIteration();
    }
    public function current()
    {
        return sprintf('%s<node>%s</node>%s',
                       str_repeat("\t", $this->getDepth() +1),
                       parent::current(),
                       PHP_EOL);
    }
}

然后像这样组装：

$iterator = new TranformArrayIterator(new RecursiveArrayIterator($nodes));

foreach($iterator as $val) {
    echo $val;
}

输出

<nodes>
        <node>parent node</node>
        <node>parent node</node>
        <nodes>
                <node>child node</node>
                <node>child node</node>
                <nodes>
                        <node>grand child node</node>
                        <node>grand child node</node>
                </nodes>
        </nodes>
</nodes>

要在使用$key时删除$key => $val，请将其添加到TraverseArrayIterator

public function key()
{ 
    return '';
}

由于您的目标似乎是生成XML，因此您还可以将XMLWriter作为协作者传递给Iterator。这允许更多地控制生成的XML，并确保输出是有效的XML：

class TranformArrayIterator extends RecursiveIteratorIterator
{
    private $xmlWriter;

    public function __construct(
        XmlWriter $xmlWriter, 
        Traversable $iterator, 
        $mode = RecursiveIteratorIterator::LEAVES_ONLY , 
        $flags = 0)
    {
        $this->xmlWriter = $xmlWriter;
        parent::__construct($iterator, $mode, $flags);
    }

    public function beginIteration()
    {
        $this->xmlWriter->startDocument('1.0', 'utf-8');
        $this->beginChildren();
    }
    public function endIteration()
    {
        $this->xmlWriter->endDocument();
    }
    public function beginChildren()
    {
        $this->xmlWriter->startElement('nodes');
    }
    public function endChildren()
    {
        $this->xmlWriter->endElement();
    }
    public function current()
    {
        $this->xmlWriter->writeElement('node', parent::current());
    }
}

然后你就这样使用它：

$xmlWriter = new XmlWriter;
$xmlWriter->openUri('php://output');
$xmlWriter->setIndent(true);
$xmlWriter->setIndentString("\t");
$iterator = new TranformArrayIterator(
    $xmlWriter,
    new RecursiveArrayIterator($nodes)
);

然后

和foreach将生成相同的输出（但添加XML序言）

Answer 2

<?php

$nodes = array(
    "parent node",
    "parent node",
    array(
        "child node",
        "child node",
        array(
            "grand child node",
            "grand child node"
        )
    )
);

$s = '<node>';
$arr = $nodes;

while(count($arr) > 0)
{
    $n = array_shift($arr);
    if(is_array($n))
    {
        array_unshift($arr, null);
        $arr = array_merge($n, $arr);
        $s .= '<node>';
    }
    elseif(is_null($n))
        $s .= '</node>';
    else
        $s .= '<node>'.$n.'</node>';
}
$s .= '</node>';

echo $s;

?>

多维数组迭代

2 个答案: