Question

我想要捕获本地POST请求并解析其数据仅用于测试，FiddlerCore应仅响应它已解析的数据这是FidlerCore封装的代码：

private void FiddlerApplication_BeforeRequest(Session oSession)
{
    if (oSession.hostname != "localhost") return;

    eventLog.WriteEntry("Handling local request...");
    oSession.bBufferResponse = true;
    oSession.utilCreateResponseAndBypassServer();
    oSession.oResponse.headers.HTTPResponseStatus = "200 Ok";
    oSession.oResponse["Content-Type"] = "text/html; charset=UTF-8";
    oSession.oResponse["Cache-Control"] = "private, max-age=0";

    string body = oSession.GetRequestBodyAsString();
    oSession.utilSetResponseBody(body);
}

以下是请求发件人的代码：

const string postData = "This is a test that posts this string to a Web server.";

try
{
    WebRequest request = WebRequest.Create("http://localhost/?action=print");
    byte[] byteArray = Encoding.UTF8.GetBytes(postData);
    request.ContentLength = byteArray.Length;
    request.ContentType = "text/html";
    request.Method = "POST";

    using (Stream stream = request.GetRequestStream())
    {
        stream.Write(byteArray, 0, byteArray.Length);
    }

    using (WebResponse response = request.GetResponse())
    {
        txtResponse.Text = ((HttpWebResponse)response).StatusDescription;
        using (Stream stream = response.GetResponseStream())
        {
            using (StreamReader streamReader = new StreamReader(stream))
            {
                string responseFromServer = streamReader.ReadToEnd();
                streamReader.Close();
                txtResponse.Text = responseFromServer;
            }
        }
    }
}
catch (Exception ex)
{
    txtResponse.Text = ex.Message;
}

我收到以下错误：

服务器提交了协议违规。节= ResponseStatusLine

我做错了什么？

Answer 1

通过改变来实现它：

WebRequest request = WebRequest.Create("http://localhost/?action=print");

到

WebRequest request = WebRequest.Create("http://localhost:8877/?action=print");

FiddlerCore正确拦截从浏览器调用此URL，而无需指定端口号。我不认为我应该插入监听端口，因为FiddlerCore应该拦截所有流量，对吗？

使用FiddlerCore解析POST请求数据

1 个答案: