Question

我有一个json数组，如下所示：

 a=   {"title":"workers","data":[{"name":"tom","id":"LBJP01Z"},{"name":"bob","id":"LBJP08Z"},{"name":"bill","id":"LBJP02Z"}]},{"title":"teachers","data":[{"name":"jill","id":"LZJP01Z"},{"name":"tim","id":"LBJP03Z"},{"name":"sam","id":"LBJP07Z"}]}

我希望得到这样的结果：

tom
bob
bill
jill
tim
sam

我的代码：

for (int i = 0; i < [a count]-1; i++) {

    for (int j = 0; j < [a[i] count]-1; j++)
    {

        NSString *str = [NSString stringWithFormat:@"%@",[[[[a objectAtIndex:i]objectForKey:@"data"]objectAtIndex:j] objectForKey:@"name"]];
        NSLog(@"%@",str);

    }
}

但最后，我得到了这样的结果：

tom
tom
tom
tom
tom
tom

Answer 1

从你的JSON，a是一个字典，而不是一个数组。获取data数组开始：

NSArray *dataArray = a[@"data"];

现在，使用KVC提取名称：

NSArray *names = [dataArray valueForKey:@"name"];

Answer 2

NSMutableDictionary *yourdict = [a JSONValue];
NSMutableArray *my_arr = [get_news objectForKey:@"data"];
[my_arr retain];

如何从另一个数组中获取数组

2 个答案: