Question

当我运行此查询时，伙计们：

SELECT * FROM big_table big
WHERE sum_number = 1
 AND NOT EXISTS ( SELECT 1
                  FROM smal_table smal
                  WHERE other_number = big.other_number
                )

我得到了4次重组，但是当我运行这个时

SELECT * FROM big_table big
WHERE sum_number = 1
 AND NOT EXISTS ( SELECT 1
                  FROM smal_table smal
                  WHERE other_number = big.other_number
                  AND NOT EXISTS ( SELECT 1
                                    FROM and_another_table another
                                    WHERE and_another_number = big.and_another_number
                                 )
                )

我从big_table获得所有行。有没有人有任何想法为什么会这样？我想做一个查询，向我展示big_table中不存在于smal_table中的所有行，但如果它存在于小表中，我只想要不在and_another_table中的行有人可以帮帮我吗？

编辑：我想要big_table中不在small_table中的行加上big_table中的行，这些行在small_table上但不在and_another_table中

Answer 1

我认为逻辑是你希望大表中的行不在小表或另一个表中。如果是这样，这应该做你想要的：

SELECT *
FROM big_table big
WHERE sum_number = 1 AND
      (NOT EXISTS (SELECT 1
                   FROM small_table smal
                   WHERE other_number = big.other_number
                  ) OR
       NOT EXISTS (SELECT 1
                   FROM and_another_table another
                   WHERE and_another_number = big.and_another_number
                  )
      );

编辑：

根据以下评论，where子句将是：

WHERE sum_number = 1 AND
      (NOT EXISTS (SELECT 1
                   FROM small_table smal
                   WHERE other_number = big.other_number
                  ) OR
       EXISTS (SELECT 1
               FROM and_another_table another
               WHERE and_another_number = big.and_another_number
              )
      );

内部不存在Oracle不存在

1 个答案: