Question

我有这个代码。在我的代码中我需要延迟操作开始（它工作正常）但在操作中我需要检查InitInProcess（）值。如果为false则为break循环，如果为true，则等待500ms并再次检查。但结果我得知检查结果是imediatly而不是每500ms。

Handler myHandler = new Handler();
        myHandler.postDelayed(new Runnable() {

            @Override
            public void run() {

                int test = 0;
                while (test!=20) 
                {
                    if (InitInProcess()) 
                        break;

                    try {
                        Thread.sleep(500);
                    } catch (InterruptedException e) {

                        e.printStackTrace();
                    }

                    Log.d("MyApp", ""+test);


                    test++;
                }

            }
        }, 3000);

记录（查看时间）：

    02-27 12:48:41.707: D/MyApp(10082): 0
    02-27 12:48:42.212: D/MyApp(10082): 1
    02-27 12:48:42.712: D/MyApp(10082): 2
    02-27 12:48:43.267: D/MyApp(10082): 3
    02-27 12:48:43.767: D/MyApp(10082): 4
    02-27 12:48:44.272: D/MyApp(10082): 5
    02-27 12:48:44.772: D/MyApp(10082): 6
    02-27 12:48:45.277: D/MyApp(10082): 7
    02-27 12:48:45.777: D/MyApp(10082): 8
    02-27 12:48:46.277: D/MyApp(10082): 9
    02-27 12:48:46.777: D/MyApp(10082): 10
    02-27 12:48:47.277: D/MyApp(10082): 11
    02-27 12:48:47.772: D/MyApp(10082): 12
    02-27 12:48:48.277: D/MyApp(10082): 13
    02-27 12:48:48.777: D/MyApp(10082): 14
    02-27 12:48:49.277: D/MyApp(10082): 15
    02-27 12:48:49.777: D/MyApp(10082): 16
    02-27 12:48:50.277: D/MyApp(10082): 17
    02-27 12:48:50.782: D/MyApp(10082): 18
    02-27 12:48:51.277: D/MyApp(10082): 19

Answer 1

 int test = 0;
 while (test!=20){
       if (InitInProcess()) 
            break;

 try {
  myHandler.postDelayed(new Runnable() {
                     test++;
 Log.d("MyApp", ""+test);
        },500);
     } catch (Exception e) {
        e.printStackTrace();
     }

}

Answer 2

private static final long RETRY_DELAY = 500;
private static final int RETRY_COUNT = 10;
private Handler myHandler = new Handler() {
        @Override
        public void handleMessage(android.os.Message msg) {
            if (!InitInProcess() && msg.what>0) {
                myHandler.sendEmptyMessageDelayed(msg.what-1, RETRY_DELAY);
            }
        }
    };

    myHandler.sendEmptyMessageDelayed(RETRY_COUNT, RETRY_DELAY);

延迟循环并暂停它

2 个答案: