Question

我正在使用一个应用程序，在此我必须在按钮单击时搜索联系人并从电话联系人中选择一个联系人。最后我想将其设置为edittext。我可以通过电话联系人搜索联系人，但我无法通过电话联系人联系。

活性：

searchBtn.setOnClickListener(new OnClickListener() {

@Override
public void onClick(View v) {
// TODO Auto-generated method stub
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
intent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE);
startActivityForResult(intent,1);

}
});
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
// TODO Auto-generated method stub
super.onActivityResult(requestCode, resultCode, data);

if(requestCode==RESULT_OK){
Uri contactData = data.getData();
Cursor cursor = managedQuery(contactData, null, null, null, null);
cursor.moveToFirst();
String number = cursor.getString(cursor.getColumnIndexOrThrow
(ContactsContract.CommonDataKinds.Phone.NUMBER));

//contactName.setText(name);
ephoneNumber.setText(number);
//contactEmail.setText(email);
}
}

Answer 1

首先为StartActivityForResult设置Intent像这样

private void pickContact() {
    Intent pickContactIntent = new Intent(Intent.ACTION_PICK, Uri.parse("content://contacts"));
    pickContactIntent.setType(Phone.CONTENT_TYPE); // Show user only contacts w/ phone numbers
    startActivityForResult(pickContactIntent, PICK_CONTACT_REQUEST);
}

然后处理从本机联系人应用程序进行意图的结果

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    // Check which request it is that we're responding to
    if (requestCode == PICK_CONTACT_REQUEST) {
        // Make sure the request was successful
        if (resultCode == RESULT_OK) {
            // Get the URI that points to the selected contact
            Uri contactUri = data.getData();
            // We only need the NUMBER column, because there will be only one row in the result
            String[] projection = {Phone.NUMBER};

            // Perform the query on the contact to get the NUMBER column
            // We don't need a selection or sort order (there's only one result for the given URI)
            // CAUTION: The query() method should be called from a separate thread to avoid blocking
            // your app's UI thread. (For simplicity of the sample, this code doesn't do that.)
            // Consider using CursorLoader to perform the query.
            Cursor cursor = getContentResolver()
                    .query(contactUri, projection, null, null, null);
            cursor.moveToFirst();

            // Retrieve the phone number from the NUMBER column
            int column = cursor.getColumnIndex(Phone.NUMBER);
            String number = cursor.getString(column);

            // Do something with the phone number...
        }
    }
}

查看其他参考链接

Link 1 Link 2

Answer 2

巴拉特，

你需要像 -

这样的许可

android:name="android.permission.READ_CONTACTS"/>

然后，调用联系人选择器

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);

然后，

@Override
public void onActivityResult(int reqCode, int resultCode, Intent data) {
super.onActivityResult(reqCode, resultCode, data);

switch (reqCode) {
case (PICK_CONTACT) :
   if (resultCode == Activity.RESULT_OK) {
    Uri contactData = data.getData();
    Cursor c =  managedQuery(contactData, null, null, null, null);
     if (c.moveToFirst()) {
      String name = c.getString(c.getColumnIndexOrThrow(People.NAME));
      // TODO Whatever you want to do with the selected contact name.
    }
  }
  break;
  }
 }

OR，换句话说你可以使用

Cursor cursor = null;
try {
    cursor = context.getContentResolver().query(Phone.CONTENT_URI, null, null, null, null);
    int contactIdIdx = cursor.getColumnIndex(Phone._ID);
    int nameIdx = cursor.getColumnIndex(Phone.DISPLAY_NAME);
    int phoneNumberIdx = cursor.getColumnIndex(Phone.NUMBER);
    int photoIdIdx = cursor.getColumnIndex(Phone.PHOTO_ID);
    cursor.moveToFirst();
    do {
        String idContact = cursor.getString(contactIdIdx);
        String name = cursor.getString(nameIdx);
        String phoneNumber = cursor.getString(phoneNumberIdx);
        //...
    } while (cursor.moveToNext());  
} catch (Exception e) {
    e.printStackTrace();
} finally {
    if (cursor != null) {
        cursor.close();
    }
}

以上解决方案很简单，适用于联系号码提取。

Answer 3

试试这个

CursorLoader cursorLoader = new CursorLoader(mActivity,
            CallLog.Calls.CONTENT_URI, null, null, null, null);
managedCursor = cursorLoader.loadInBackground();
int number = managedCursor.getColumnIndex(CallLog.Calls.NUMBER);
int name = managedCursor.getColumnIndex(CallLog.Calls.CACHED_NAME);
String conTactnumber=managedCursor.getString(number);               
String contactname=managedCursor.getString(name);

set permission   
<uses-permission android:name="android.permission.READ_CONTACTS" >
</uses-permission>

搜索联系人并从Android手机联系人处获取联系电话

3 个答案: