我对python完全不熟悉。因此，请完整地解释我的回答。
在我的代码中我想测量玩家在光标接触屏幕上的弹跳球之前持续的时间，但我获得的时间是自第一次命令初始化以来所有秒数的总和。我需要在用户结束游戏后立即停止计算秒数并重新开始再次播放选项......
另外，如果没有检测到鼠标的位置，我可以通过一种方式让玩家有资格进入下一级别......因为dat会使程序代码逻辑错误......
here is my code:
import pygame,sys
from pygame.locals import*
from pygame import *
import random
def main():
# set up sounds
# import pygame
#gameOverSound = pygame.mixer.Sound('gameover.wav')
#pygame.mixer.music.load('background.mid')
#from pygame import *
#import random
#pygame.mixer.pre_init(44100, 16, 2, 4096)
#background =image.load('C:\Users\Administrator\Desktop\oearth.png')
ballpic = image.load('ball1.png')
ballpic.set_colorkey((0,0,0))
#find a way to include verification of more than one colour key
# to add more than one shape....pending
numballs = 10
delay = 5
done = False
balls = []
stars = []
#generate an if loop for execution of both the parts
k = 2
init()
screen = display.set_mode((640, 480))
display.set_caption('mouse game by shivangi and ananya')
event.set_grab(1)
#pygame.time.Clock() Creates a Clock object (assign this to a name), which you can then call the tick() method on
#to find out how much time has passed since the last time you called tick()
#pygame.time.delay(milliseconds) Pauses game for time specified
#pygame.time.get_ticks() Returns the number of milliseconds passed since pygame.init() was #called
for count in range(numballs):
balls.append(dict)
balls[count] = {'x': 0, 'y': 0, 'xmove': random.randint(1, 2), 'ymove': random.randint(1, 2)}
screen = display.set_mode((640, 480)) #####screen = display.set_mode((640,480),FULLSCREEN,32).....check functioning...
#pygame.display.list_modes()
#[(800, 600), (1280, 1024), (1280, 960), (1280, 800), (1280, 768), (1280, 720),
#(1152, 864), (1088, 612), (1024, 768), (960, 600), (848, 480), (800, 600),
#(720, 576), (720, 480), (640, 480), (640, 400), (512, 384), (480, 360), (400, 300),
#(320, 240), (320, 200), (640, 480)]
while done == False:
pygame.time.Clock()
init()
screen.fill((0,100,0))
for count in range(numballs):
screen.blit(ballpic, (balls[count]['x'], balls[count]['y']))
display.update()
time.delay(delay)
for count in range(numballs):
balls[count]['x'] = balls[count]['x'] + balls[count]['xmove']
balls[count]['y'] = balls[count]['y'] + balls[count]['ymove']
for count in range(numballs):
if balls[count]['x'] > 620:
balls[count]['xmove'] = random.randint(-2, 0)
if balls[count]['x'] < -10:
balls[count]['xmove'] = random.randint(0, 6)
if balls[count]['y'] > 470:
balls[count]['ymove'] = random.randint(-9, 0)
if balls[count]['y'] < -10:
balls[count]['ymove'] = random.randint(0, 5)
for e in event.get():
if e.type == KEYUP:
if e.key == K_ESCAPE:
done = True
if screen.get_at((mouse.get_pos())) == (227,209,43):
done = True
if done == True:
#pygame.mixer.init()
break
sec = time.get_ticks()/1000
quit()
while sec < k:
print "you lasted for only",sec,"seconds...try again to qualify for the next level..."
quit()
break
time_lasted = 0
while sec >= k:
starpic = image.load('star.png')
starpic.set_colorkey((0,0,0))
#find a way to include verification of more than one colour key...PENDING
numstars = 30
delay = 8
done = False
stars = []
for count in range(numstars):
stars.append(dict)
stars[count] = {'x': 0, 'y': 0, 'xmove': random.randint(1, 2), 'ymove': random.randint(1, 2)}
screen = display.set_mode((640, 480))
display.set_caption('mouse game')
event.set_grab(1)
while done == False:
init()
screen.fill((160,32,240))
for count in range(numstars):
screen.blit(starpic, (stars[count]['x'], stars[count]['y']))
display.update()
time.delay(delay)
for count in range(numstars):
stars[count]['x'] = stars[count]['x'] + stars[count]['xmove']
stars[count]['y'] = stars[count]['y'] + stars[count]['ymove']
for count in range(numstars):
if stars[count]['x'] > 620:
stars[count]['xmove'] = random.randint(-2, 0)
if stars[count]['x'] < -10:
stars[count]['xmove'] = random.randint(0, 2)
if stars[count]['y'] > 470:
stars[count]['ymove'] = random.randint(-2, 0)
if stars[count]['y'] < -10:
stars[count]['ymove'] = random.randint(0, 2)
for e in event.get():
if e.type == KEYUP:
if e.key == K_ESCAPE:
done = True
if screen.get_at((mouse.get_pos())) == (255,255,255,255):
done = True
if done == True:
time_lasted = time.get_ticks()/1000
quit()
break
#sec = time.update()
#time_lasted = time.update()
#correction of time error to be done....pending....
quit()
print "You lasted for", sec, "seconds in the first level!"
print "\n"
print "you lasted for",time_lasted,"in the second level!"
print "\n"
print "your total score is :", int(sec) + int(time_lasted)
print "\n"
print "game over...! Thank you for playing!! :D :P :)"
quit()
break
main()
x = 1
x = raw_input("Do you want to play again?")
while x.upper() in ['YES','Y']:
main()
x = raw_input("Do you want to play again?")
while x.upper() in ['NO','N']:
break
答案 0 :(得分：1)
# when player starts game
start = time.get_ticks()
# during game
current = time.get_ticks()
time_you_played = (current - start)/1000
编辑：
计时秒数。
class Timer():
def __init__(self):
self._start = 0
def start(self):
self._start = pygame.time.get_ticks()
def current(self):
return (pygame.time.get_ticks() - self._start)/1000
示例 - 使用方法：
import pygame
# add class Timer here
pygame.init()
t = Timer()
t.start() # start or restart timer
pygame.time.wait(3000) # for test only
print t.current() # print seconds
pygame.time.wait(2000) # for test only
print t.current() # print seconds
您不必停止计时器，因为您可以使用start()重新启动计时器。