Question

在下面的代码中，我使用的是Oracle 11g表达式版本。获取列数据时，如果源为NUMBER（16,3）但绑定数据为SQL_C_DOUBLE，则转换中似乎存在一些错误。

using System;
using System.Data.Odbc;

namespace OracleNumberConversionTestCSharp
{
   class Program
   {
      static void Main(string[] args)
      {
         OdbcConnection connection = new OdbcConnection();

         connection.ConnectionString = "Driver={Oracle in OraClient12Home1}; Dbq=127.0.0.1/XE; Uid=System; Pwd=password;";

         connection.Open();

         //Drop the table from a previous run
         OdbcCommand command = new OdbcCommand("DROP TABLE ORACLE_NUMBER_TEST",connection);

         try
         {
            //would fail if table hasn't been created yet
            command.ExecuteNonQuery();
         }
         catch
         {

         }

         //Create the table
         command = new OdbcCommand("CREATE TABLE ORACLE_NUMBER_TEST (MYNUM NUMBER(16,3))",connection);

         command.ExecuteNonQuery();

         //Insert the value
         command = new OdbcCommand("INSERT INTO ORACLE_NUMBER_TEST (MYNUM) values (2014056132407.123)",connection);

         command.ExecuteNonQuery();

         //Get the value back from the db
         command = new OdbcCommand("SELECT MYNUM FROM ORACLE_NUMBER_TEST",connection);

         OdbcDataReader reader = command.ExecuteReader();

         if (reader.HasRows)
         {
            double expected = 2014056132407.123;
            double actual = reader.GetDouble(0);

            Console.WriteLine("Actual   = " + actual.ToString("R"));
            Console.WriteLine("Expected = " + expected.ToString("R"));
         }
      }
   }
}

结果是：

Actual   = 2014056132407.12
Expected = 2014056132407.123

使用以下几种方法解决了这个问题：

将SELECT语句更改为：SELECT CAST (MYNUM AS BINARY_DOUBLE) FROM ORACLE_NUMBER_TEST
将代码从double actual = reader.GetDouble(0);更改为double actual = Convert.ToDouble(reader.GetDecimal(0));

如果我在C中编写示例，我会得到相同的行为.SQL Server和MySQL中的类似SQL会返回预期的结果。这看起来像是Oracle驱动程序中从Oracle NUMBER转换为double的错误，还是在可接受行为的参数范围内？

Oracle NUMBER加倍bug？

0 个答案: