循环读EEPROM

Question

我试图从PIC16F84中初始化的EEPROM中读取信息（在MPLAB中模拟），并且无法理解，为什么在调试器中我总是得到二进制'1010'（=十六进制为0x0A），但在EEPROM中有3个值。我没有正确地初始化它们或者可能以不同的顺序排列其他值？         列表p = 16F84         基数十六进制

;---------------------------------------------------------------------
RP0         equ 5
STATUS      equ 0x03
EEDATA      equ 0x08
EEADR       equ 0x09
EECON1      equ 0x88
RD          equ 0
;----------------------------------------------------------------------
counter     equ 0x10   
pointer     equ 0x15        
;----------------------------------------------------------------------
BANK0   macro
            bcf STATUS, RP0
        endm

BANK1   macro
            bsf STATUS, RP0
        endm
;----------------------------------------------------------------------

        org         0x2100      ; EEPROM Data
        de          b'1010', b'0110', b'0001'

        org         0x0000      
        goto        start      

start:
        BANK0

        clrw                    ; WREG = 0
        movlw       3           ; WREG = 3
        movwf       counter     ; counter = WREG => 3

init:
        clrw                    ; WREG = 0

read_data:
        incf        pointer, 1  ; pointer += 1
        movf        pointer, 0  ; WREG = pointer

        movfw       EEADR       ; get address
        BANK1
        bsf         EECON1, RD  ; read
        BANK0
        movf        EEDATA, W   ; WREG = EEDATA

        goto        read_data   


done_loop:
        goto done_loop
        end

Answer 1

你有两个错误！

1）在开始读取EEPROM时设置指针值，如：

movl    1 
movwf   pointer

2）变化：

movfw       EEADR       ; get address

到...

movwf       EEADR       ; set address