从php json输出中删除换行符

时间：2014-02-26 20:59:32

标签： php json postgresql

经过几个小时的搜索和努力，我无法解决它。所以最后寻求你的帮助。

我的Json 

[
{
    "notice_id": "2",
    "n_header": "Class Test",
    "n_subject": "Class Test from 15-jan",
    "n_datetime": "2014-01-05 09:00:00",
    "noticenum": "NISTA1",
    "n_body": "Dear Students Class test 1 will be held from january 15. \nDetaled Notice will be notified further with timetable",
    "n_removeby": "2014-01-05",
    "n_givenby": "7",
    "nconcerned_id": "1",
    "nconcerned_batch": "2010",
    "nconcerned_degree": "BTECH",
    "nconcerned_section": " "
},
{
    "notice_id": "3",
    "n_header": "Comprehensive Viva",
    "n_subject": "Comprehensive viva from 20-feb",
    "n_datetime": "2014-02-05 10:00:00",
    "noticenum": "NISTB1",
    "n_body": "Students under me for comprehensive\n viva are hereby informed to clear their viva before 20th feb. After 20 feb no viva would be entertained under me.",
    "n_removeby": "2014-02-21",
    "n_givenby": "1",
    "nconcerned_id": "4",
    "nconcerned_batch": "2010",
    "nconcerned_degree": "BTECH",
    "nconcerned_section": "IT"
}
]

然而，当我在浏览器中看到它时，它看起来像：

a http://www.4shared.com/download/D1UQsmEbce/json.png?lgfp=3000

正如你所看到的那样，它不合时宜地被破坏了。结果当我parse我的android app我得到了一个异常value <br of type java.lang.String can't be converted to JSONArray我认为这是因为linebreak这个问题仅

我尝试了什么

我尝试了许多内容，包括preg_replace，str_replace等以逃避\r\n or <br>等但无法让它为我工作。最后我有一个我正在使用的功能这个：

function parse($text) {

$text = str_replace("\r\n", "\n", $text);
$text = str_replace("\r", "\n", $text);
$text = trim( preg_replace( '/\s+/', '<br/>', $text));
// JSON requires new line characters be escaped
 $text = str_replace("\n", "\\n", $text);
return $text;

}

我正在编写一个查询来从postgresql database检索数据。运行以下循环。

for ($i=0; $i<$rows; $i++)
{

$row = pg_fetch_array($result, $i, PGSQL_ASSOC);

$json['notice_id'] = trim(strip_tags($row['notice_id']));
$json['n_header'] = trim(strip_tags($row['n_header']));
$json['n_subject'] = trim(strip_tags($row['n_subject']));
$json['n_datetime'] = trim(strip_tags($row['n_datetime']));
$json['noticenum'] = trim(strip_tags($row['noticenum']));
$json['n_body'] = trim(strip_tags($row['n_body']));
$json['n_removeby']=  trim(strip_tags($row['n_removeby']));
$json['n_givenby'] = trim(strip_tags($row['n_givenby']));
$json['nconcerned_id'] = trim(strip_tags($row['nconcerned_id']));
$json['notice_id'] = trim(strip_tags($row['notice_id']));
$json['nconcerned_batch'] = trim(strip_tags($row['nconcerned_batch']));
$json['nconcerned_degree'] = trim(strip_tags($row['nconcerned_degree']));
$json['nconcerned_section'] = trim(strip_tags($row['nconcerned_section']));

parse($json['notice_id']); 
parse($json['n_header']); 
parse($json['n_subject']); 
parse($json['n_datetime']); 
parse($json['noticenum']); 
parse($json['n_removeby']); 
parse($json['n_givenby']); 
parse($json['nconcerned_id']); 
parse($json['notice_id']); 
parse($json['nconcerned_batch']); 
parse($json['nconcerned_degree']); 
parse($json['nconcerned_section']); 


$data[] = $json;


}

$h = json_encode($data);

echo $h ;


}

问题

我怎样才能摆脱这个问题并得到一个整洁的json，这不会产生任何jsonexception？

注意：

我仔细检查过那里的换行符。但我的数据库中没有换行符（\n）等。

已编辑的代码 

$data = array ();
for ($i=0; $i<$rows; $i++)
{

$row = pg_fetch_array($result, $i, PGSQL_ASSOC);

$json['notice_id'] = $row['notice_id'];
$json['n_header'] = $row['n_header'];
$json['n_subject'] = $row['n_subject'];
$json['n_datetime'] = $row['n_datetime'];
$json['noticenum'] = $row['noticenum'];
$json['n_body'] = $row['n_body'];
$json['n_removeby']=  $row['n_removeby'];
$json['n_givenby'] = $row['n_givenby'];
$json['nconcerned_id'] = $row['nconcerned_id'];
$json['notice_id'] = $row['notice_id'];
$json['nconcerned_batch'] = $row['nconcerned_batch'];
$json['nconcerned_degree'] = $row['nconcerned_degree'];
$json['nconcerned_section'] = $row['nconcerned_section'];


$json['notice_id']=parse($json['notice_id']); 
$json['n_header']=parse($json['n_header']); 
$json['n_subject']= parse($json['n_subject']); 
$json['n_datetime']=parse($json['n_datetime']); 
$json['noticenum']=parse($json['noticenum']); 
$json['n_removeby']=parse($json['n_removeby']); 
$json['n_givenby']=parse($json['n_givenby']); 
$json['nconcerned_id']=parse($json['nconcerned_id']); 
$json['notice_id']=parse($json['notice_id']); 
$json['nconcerned_batch']=parse($json['nconcerned_batch']); 
$json['nconcerned_degree']=parse($json['nconcerned_degree']); 
$json['nconcerned_section']=parse($json['nconcerned_section']); 


$data[] = $json;

}

$h = json_encode($data);

echo $h ;

现在在浏览器中输出

a http://www.4shared.com/download/C4lUKR-1ba/json1.png?lgfp=3000

这是另一个json，它在我的浏览器中整齐地显示出来。

a http://www.4shared.com/download/tNWhDbfuce/ajson.png?lgfp=3000

奇怪为什么另一个人没有换行！

奇怪的解决方案

我不确定是什么解决了这个问题。但是当我更改了url我正在使用的php来执行我的{{1}}文件并且它对我有用时。请参考here

3 个答案:

答案 0 :(得分：4)

您误解了浏览器的显示内容。请记住，JSON本质上是纯文本，但您的浏览器正在尝试将其显示为HTML。 \n字符不受HTML模式显示的支持，它们将文本包装在第一个适当的空格字符处。 JSON可以毫不费力地将\n字符保留在字符串中。

您的<br>错误很可能来自您<br>电话中的preg_replace插件，因为原始JSON中没有<br>个标签。换句话说，通过尝试修复错误，如果您没有尝试修复错误，则会导致您尝试修复的错误。

答案 1 :(得分：1)

根据您的输入确定我完成了工作示例，具体取决于堆栈溢出时的一些答案，Parse JSON from URLon android。

PHP部分
我有你的数据，所以我做了这样的例子

<?php

$row = array ( 
    "notice_id" => "2",
    "n_header" => "Class Test",
    "n_subject" => "Class Test from 15-jan",
    "n_datetime" => "2014-01-05 09:00:00",
    "noticenum" => "NISTA1",
    "n_body" => "Dear Students Class test 1 will be held from january 15. \nDetaled Notice will be notified further with timetable",
    "n_removeby" => "2014-01-05",
    "n_givenby" => "7",
    "nconcerned_id" => "1",
    "nconcerned_batch" => "2010",
    "nconcerned_degree" => "BTECH",
    "nconcerned_section" => " ");
$row2 = array ("notice_id" => "3",
    "n_header" => "Comprehensive Viva",
    "n_subject" => "Comprehensive viva from 20-feb",
    "n_datetime" => "2014-02-05 10:00:00",
    "noticenum" => "NISTB1",
    "n_body" => "Students under me for comprehensive\n viva are hereby informed to clear their viva before 20th feb. After 20 feb no viva would be entertained under me.",
    "n_removeby" => "2014-02-21",
    "n_givenby" => "1",
    "nconcerned_id" => "4",
    "nconcerned_batch" => "2010",
    "nconcerned_degree" => "BTECH",
    "nconcerned_section" => "IT");
$data [] =$row;
$data [] = $row2;
echo json_encode ($data);

Android部分 

class MyAsyncTask extends AsyncTask<String, String, Void> {

        private ProgressDialog progressDialog = new ProgressDialog(MainActivity.this);
        InputStream inputStream = null;
        String result = ""; 

        protected void onPreExecute() {
            progressDialog.setMessage("Downloading your data...");
            progressDialog.show();
            progressDialog.setOnCancelListener(new OnCancelListener() {
                public void onCancel(DialogInterface arg0) {
                    MyAsyncTask.this.cancel(true);
                }
            });
        }

        @Override
        protected Void doInBackground(String... params) {

            String url_select = "http://192.168.10.206/test.php";

                    ArrayList<NameValuePair> param = new ArrayList<NameValuePair>();

            try {
                // Set up HTTP post

                // HttpClient is more then less deprecated. Need to change to URLConnection
                HttpClient httpClient = new DefaultHttpClient();

                HttpPost httpPost = new HttpPost(url_select);
                httpPost.setEntity(new UrlEncodedFormEntity(param));
                HttpResponse httpResponse = httpClient.execute(httpPost);
                HttpEntity httpEntity = httpResponse.getEntity();

                // Read content & Log
                inputStream = httpEntity.getContent();
            } catch (UnsupportedEncodingException e1) {
                Log.e("UnsupportedEncodingException", e1.toString());
                e1.printStackTrace();
            } catch (ClientProtocolException e2) {
                Log.e("ClientProtocolException", e2.toString());
                e2.printStackTrace();
            } catch (IllegalStateException e3) {
                Log.e("IllegalStateException", e3.toString());
                e3.printStackTrace();
            } catch (IOException e4) {
                Log.e("IOException", e4.toString());
                e4.printStackTrace();
            }
            // Convert response to string using String Builder
            try {
                BufferedReader bReader = new BufferedReader(new InputStreamReader(inputStream, "iso-8859-1"), 8);
                StringBuilder sBuilder = new StringBuilder();

                String line = null;
                while ((line = bReader.readLine()) != null) {
                    sBuilder.append(line + "\n");
                }

                inputStream.close();
                result = sBuilder.toString();

            } catch (Exception e) {
                Log.e("StringBuilding & BufferedReader", "Error converting result " + e.toString());
            }
            return null;
        } // protected Void doInBackground(String... params)

        protected void onPostExecute(Void v) {
            //parse JSON data
            try {
                JSONArray jArray = new JSONArray(result);    
                for(int i=0; i < jArray.length(); i++) {

                    JSONObject jObject = jArray.getJSONObject(i);

                    String name = jObject.getString("n_body");
                    String tab1_text = jObject.getString("n_removeby");
                    int active = jObject.getInt("notice_id");
                    Log.i("NAME",name);
                    Log.i("REMOVE",tab1_text);
                } // End Loop
                this.progressDialog.dismiss();
            } catch (JSONException e) {
                Log.e("JSONException", "Error: " + e.toString());
            } // catch (JSONException e)
        } // protected void onPostExecute(Void v)
    } //class MyAsyncTask extends AsyncTask<String, String, Void>

不要忘记在某个地方调用MyAsync任务。

MyAsyncTask task = new MyAsyncTask();
        task.execute();

这个工作非常好，所以请查看你的安卓代码，我相信问题来自他们，希望这对你有帮助。

答案 2 :(得分：0)

您只需在解码之前添加新行，它将可以100％工作：

$text = str_replace("\r\n", "\n", $text);
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