是否有任何API可以在Eclipse项目中获取特定内容类型的所有文件?
一种选择是访问所有资源并收集内容类型的文件。
我正在寻找将IProject和内容类型id作为参数并返回IPath或IFile或IResource对象的API。例如,获取项目中的所有Java文件。
提前致谢。
答案 0 :(得分:3)
这就是我用来查找当前项目中所有c文件的内容:
public static ArrayList<IResource> getAllCFilesInProject(){
ArrayList<IResource> allCFiles = new ArrayList<IResource>();
IWorkspaceRoot myWorkspaceRoot = ResourcesPlugin.getWorkspace().getRoot();
IProject project = FileParaviserUtils.getCurrentProject();
IPath path = project.getLocation();
recursiveFindCFiles(allCFiles,path,myWorkspaceRoot);
return allCFiles;
}
private static void recursiveFindCFiles(ArrayList<IResource> allCFiles,IPath path, IWorkspaceRoot myWorkspaceRoot){
IContainer container = myWorkspaceRoot.getContainerForLocation(path);
try {
IResource[] iResources;
iResources = container.members();
for (IResource iR : iResources){
// for c files
if ("c".equalsIgnoreCase(iR.getFileExtension()))
allCFiles.add(iR);
if (iR.getType() == IResource.FOLDER){
IPath tempPath = iR.getLocation();
recursiveFindCFiles(allCFiles,tempPath,myWorkspaceRoot);
}
}
} catch (CoreException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static IProject getCurrentProject(){
IWorkbenchWindow window = PlatformUI.getWorkbench().getActiveWorkbenchWindow();
if (window != null)
{
IStructuredSelection selection = (IStructuredSelection) window.getSelectionService().getSelection();
Object firstElement = selection.getFirstElement();
if (firstElement instanceof IAdaptable)
{
IProject project = (IProject)((IAdaptable)firstElement).getAdapter(IProject.class);
return project;
}
}
return null;
}
答案 1 :(得分:2)
不,没有。你的想法通常是如何做到的。
答案 2 :(得分:0)
release notes of eclipse3.1当时(2005年6月)确实提到了内容类型匹配的启发式更改。
它与bug 90218相关,是bug 82986的一部分(3.1中匹配的增强),引用bug 86862(“需要相关自定义对象查找的API”)
该API没有成功,但code is available可供您重复使用。
public Object[] findRelatedObjects(IContentType type, String fileName, IRelatedRegistry registry) {
List allRelated = new ArrayList();
// first add any objects directly related to the content type
Object[] related = registry.getRelatedObjects(type);
for (int i = 0; i < related.length; i++) {
allRelated.add(related[i]);
}
// backward compatibility requested - add any objects related to the file name
if (fileName != null) {
related = registry.getRelatedObjects(fileName);
for (int i = 0; i < related.length; i++) {
if (!allRelated.contains(related[i])) {
// we don't want to return duplicates
allRelated.add(related[i]);
}
}
}
// now add any indirectly related objects, walking up the content type hierarchy
while ((type = type.getBaseType()) != null) {
related = registry.getRelatedObjects(type);
for (int i = 0; i < related.length; i++) {
if (!allRelated.contains(related[i])) {
// we don't want to return duplicates
allRelated.add(related[i]);
}
}
}
return allRelated.toArray();
}