Question

我一直试图让Nodesagencys CakePHP Platform-API-plugin使用我的Cake应用程序几天，但现在没有成功。你能否指出我正确的方向？

当我通过jQuerys admin_add()尝试发布到我的add()或$.ajax方法时，我只返回views/$Controller/json/admin_index.ctp（或index.ctp}， views/$Controller/json/admin_add.ctp template。

请求似乎已经过身份验证，并且在开发工具中可以作为POST（200）查看，但无论我做什么，我只返回index.ctp视图，而不是admin_add。

继承人ajax链接：

$.ajax({
    type: "POST",
    url: "http://dev.mydomain.co.uk/faqArticles.json?token=" + userToken,
    data: data,
    dataType: "json",

继承了admin_add方法

public function admin_add() {

    // New API code 
    $this->Api->denyPublic('add');

    if ($this->request->is('post')) {

        if ($this->request->is('api')) {

            if ($this->request->is('json')) {

                // Need to add the current auth'd users to this request data here
                $this->request->data['user_id'] = $this->Auth->user('id');

                // Get JSON encoded data submitted to a PUT/POST action
                $data = $this->request->input('json_decode');

                $this->FaqArticle->create();
                if ($this->FaqArticle->save($data)) {

                    // Get the id of the just created post to pass back to client for future updates.
                    $caId = $this->FaqArticle->getInsertID();
                    $success = true;

                } else {

                    $caId = null;
                    $success = false;
                }

                $this->set(compact('success', 'caId'));

            }

        } else {

            // Normal CRUD stuff
            $this->FaqArticle->create();

            // Assigned logged in users to article
            $this->request->data['FaqArticle']['user_id'] = $this->Auth->user('id');

            if ($this->FaqArticle->save($this->request->data)) {
                $this->Session->setFlash('The faq article has been saved', 'flash_success');
                $this->redirect(array('action' => 'index'));
            } else {
                $this->Session->setFlash('The faq article could not be saved. Please, try again.', 'flash_failure');
            }

        }
    }


    $users = $this->FaqArticle->User->find('list');
    $faqCategories = $this->FaqArticle->FaqCategory->find('list');
    $this->set(compact('users', 'faqCategories'));

    // Set layout
    $this->layout = 'admin';

}

views / faqArticles / json / admin_index.ctp看起来像：

<?php
$this->set('success', true);
$this->set('data', "ADMIN INDEX");
echo json_encode(compact('success', 'data'));
?>

views / faqArticles / json / admin_add.ctp看起来像：

<?php
$this->set('success', true);
$this->set('data', "ADMIN ADD");
echo json_encode(compact('success', 'data'));
?>

来自每个POST的回复是：

{
  "success":true,
  "data":"ADMIN INDEX",
...

这应返回admin_add JSON视图，但按上述方式获取ADMIN INDEX ...

显然我做错了什么但是什么？任何帮助都会很棒。

谢谢

Answer 1

当你发出Ajax请求时，我认为你只是链接到错误的页面（索引页而不是admin_add）我希望你的ajax请求看起来更像这样：

$.ajax({
type: "POST",
url: "http://dev.mydomain.co.uk/admin/faqArticles/add.json?token=" + userToken,
data: data,
dataType: "json"});

POST到CakePHP API时返回错误的JSON视图

1 个答案: