对称属性的OWL DL查询

Question

我正在尝试组建一个小型本体（类HP，类HEWLETT_PACKARD通过对称属性链接在一起）。猫头鹰在下面。我想要做的是在Protege中查询“equal_symmetric only hp”或“equal_symmetric only hewlett_packard”并获得对方公司。基本上我想获得每个公司名称的同义词。

    <owl:ObjectProperty rdf:about="ontologies/2014/1/untitled-ontology-2#equal_symmetric">
        <rdf:type rdf:resource="&owl;SymmetricProperty"/>
    </owl:ObjectProperty>

    <owl:Class rdf:about="ontologies/2014/1/untitled-ontology-2#hewlett_packard">
        <owl:equivalentClass>
            <owl:Restriction>
                <owl:onProperty rdf:resource="ontologies/2014/1/untitled-ontology-2#equal_symmetric"/>
                <owl:allValuesFrom rdf:resource="ontologies/2014/1/untitled-ontology-2#hp"/>
            </owl:Restriction>
        </owl:equivalentClass>        
    </owl:Class>

    <owl:Class rdf:about="ontologies/2014/1/untitled-ontology-2#hp">
        <rdfs:subClassOf rdf:resource="ontologies/2014/1/untitled-ontology-2#brand"/>
    </owl:Class>

Answer 1

如果你有两个课程并且你试图说它们是相同的，那么你应该只使用一个等价的类公理。在Protégé和RDF / XML中，它看起来像这样：

<rdf:RDF
    xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
    xmlns="http://stackoverflow.com/q/22047101/1281433/ontology#"
    xmlns:owl="http://www.w3.org/2002/07/owl#"
    xmlns:xsd="http://www.w3.org/2001/XMLSchema#"
    xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#">
  <owl:Ontology rdf:about="http://stackoverflow.com/q/22047101/1281433/ontology"/>
  <owl:Class rdf:about="http://stackoverflow.com/q/22047101/1281433/ontology#HEWLETT_PACKARD">
    <owl:equivalentClass>
      <owl:Class rdf:about="http://stackoverflow.com/q/22047101/1281433/ontology#HP"/>
    </owl:equivalentClass>
  </owl:Class>
</rdf:RDF>

如果使用DL查询，则可以看到等效的类：