如何用javascript中的这些符号“aceeisuuz”替换这些符号“ąčęėįšųūž”?我知道我需要使用正则表达式,但我无法制作模式。
这就是我所拥有的
var string = $(this).val();
string = string.replace(/\s+/g, '-').toLowerCase();
string = string.replace(/[^a-zA-Z0-9-]/g,'_');
string = regExp something here...
$("#custom_url").val(string);
更新
在其他帖子中找到了这个解决方案:
function convert_accented_characters(str){
var conversions = new Object();
conversions['ae'] = 'ä|æ|ǽ';
conversions['oe'] = 'ö|œ';
conversions['ue'] = 'ü';
conversions['Ae'] = 'Ä';
conversions['Ue'] = 'Ü';
conversions['Oe'] = 'Ö';
conversions['A'] = 'À|Á|Â|Ã|Ä|Å|Ǻ|Ā|Ă|Ą|Ǎ';
conversions['a'] = 'à|á|â|ã|å|ǻ|ā|ă|ą|ǎ|ª';
conversions['C'] = 'Ç|Ć|Ĉ|Ċ|Č';
conversions['c'] = 'ç|ć|ĉ|ċ|č';
conversions['D'] = 'Ð|Ď|Đ';
conversions['d'] = 'ð|ď|đ';
conversions['E'] = 'È|É|Ê|Ë|Ē|Ĕ|Ė|Ę|Ě';
conversions['e'] = 'è|é|ê|ë|ē|ĕ|ė|ę|ě';
conversions['G'] = 'Ĝ|Ğ|Ġ|Ģ';
conversions['g'] = 'ĝ|ğ|ġ|ģ';
conversions['H'] = 'Ĥ|Ħ';
conversions['h'] = 'ĥ|ħ';
conversions['I'] = 'Ì|Í|Î|Ï|Ĩ|Ī|Ĭ|Ǐ|Į|İ';
conversions['i'] = 'ì|í|î|ï|ĩ|ī|ĭ|ǐ|į|ı';
conversions['J'] = 'Ĵ';
conversions['j'] = 'ĵ';
conversions['K'] = 'Ķ';
conversions['k'] = 'ķ';
conversions['L'] = 'Ĺ|Ļ|Ľ|Ŀ|Ł';
conversions['l'] = 'ĺ|ļ|ľ|ŀ|ł';
conversions['N'] = 'Ñ|Ń|Ņ|Ň';
conversions['n'] = 'ñ|ń|ņ|ň|ʼn';
conversions['O'] = 'Ò|Ó|Ô|Õ|Ō|Ŏ|Ǒ|Ő|Ơ|Ø|Ǿ';
conversions['o'] = 'ò|ó|ô|õ|ō|ŏ|ǒ|ő|ơ|ø|ǿ|º';
conversions['R'] = 'Ŕ|Ŗ|Ř';
conversions['r'] = 'ŕ|ŗ|ř';
conversions['S'] = 'Ś|Ŝ|Ş|Š';
conversions['s'] = 'ś|ŝ|ş|š|ſ';
conversions['T'] = 'Ţ|Ť|Ŧ';
conversions['t'] = 'ţ|ť|ŧ';
conversions['U'] = 'Ù|Ú|Û|Ũ|Ū|Ŭ|Ů|Ű|Ų|Ư|Ǔ|Ǖ|Ǘ|Ǚ|Ǜ';
conversions['u'] = 'ù|ú|û|ũ|ū|ŭ|ů|ű|ų|ư|ǔ|ǖ|ǘ|ǚ|ǜ';
conversions['Y'] = 'Ý|Ÿ|Ŷ';
conversions['y'] = 'ý|ÿ|ŷ';
conversions['W'] = 'Ŵ';
conversions['w'] = 'ŵ';
conversions['Z'] = 'Ź|Ż|Ž';
conversions['z'] = 'ź|ż|ž';
conversions['AE'] = 'Æ|Ǽ';
conversions['ss'] = 'ß';
conversions['IJ'] = 'IJ';
conversions['ij'] = 'ij';
conversions['OE'] = 'Œ';
conversions['f'] = 'ƒ';
for(var i in conversions){
var re = new RegExp(conversions[i],"g");
str = str.replace(re,i);
}
return str;
}
答案 0 :(得分:0)
变音符问题? Similar(如果不重复)
尝试这样的事情。除非你捏别人的实现,否则请自己指定它们。匿名类型包含所有转换,我认为这是一个非常简洁的方式。但这是你可能不需要重新发明轮子的事情之一。
function myReplace(str) {
var map = {"á":"a", "ç":"c"}
for (var i in map) {
str = str.replace(new RegExp(i, "g"), map[i]);
}
return str;
}
顺便说一句,这类问题让我错过了StringBuilder。在这样的循环中编辑str对于大字符串是非常糟糕的。