Question

我正在尝试创建一个Spring集成Web应用程序，它将通过REST服务调用接收的任何有效负载转发到标准输出（稍后将由另一个后端端点替换）。

我在发布到weblogic后尝试访问网络服务器的网址

http://localhost:7001/ws_inboundBlobDispatcher/rest/services/inboundBlobDispatch/110/publish

我收到404错误。我不知道为什么会这样，或者是否正在创建其余端点。

我的整个弹簧配置如下：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/integration
        http://www.springframework.org/schema/integration/spring-integration.xsd
        http://www.springframework.org/schema/integration/http
        http://www.springframework.org/schema/integration/http/spring-integration-http.xsd
        http://www.springframework.org/schema/integration/stream
        http://www.springframework.org/schema/integration/stream/spring-integration-stream.xsd"
    xmlns:int="http://www.springframework.org/schema/integration"
    xmlns:int-http="http://www.springframework.org/schema/integration/http"
    xmlns:stream="http://www.springframework.org/schema/integration/stream">

    <int:annotation-config/>

    <!-- Inbound/Outbound Channels -->
    <int:channel id="inboundBlobMessages" />
    <int:channel id="inboundBlobResponse" />

    <int-http:inbound-gateway id="inboundEmployeeSearchRequestGateway"
        supported-methods="GET, POST"
        request-channel="inboundBlobMessages"
        reply-channel="inboundBlobResponse"
        mapped-response-headers="Return-Status, Return-Status-Msg, HTTP_RESPONSE_HEADERS"
        path="/rest/services/inboundBlobDispatch/{uniqueKey}/publish"
        reply-timeout="50000"
         />

    <stream:stdout-channel-adapter channel="inboundBlobMessages" append-newline="true"/>

</beans>

以下是我的web.xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="2.4"
    xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
    <display-name>YourSimpleWebAppNameHere</display-name>

    <servlet>
        <servlet-name>rest</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>rest</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <session-config>
        <session-timeout>60</session-timeout>
    </session-config>

</web-app>

rest-servlet.xml如下所示：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:p="http://www.springframework.org/schema/p" 
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
            http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">


</beans>

Answer 1

我相信你的<int-http:inbound-gateway/>必须在servlet上下文中（你的是空的，对吧？）。您还有一个重复的/rest路径前缀（如果您为端口中的请求映射中不需要它的servlet定义它）。

spring integration rest service抛出404错误

1 个答案: