从GET参数,我想从我的实体获取信息。
在我看来,我创建了一个包含3个选择(不是多个选择)的表单,如下所示:
http://pix.toile-libre.org/upload/original/1393414663.png
如果我只按用户过滤,我会在网址中显示:?category = 0& user = 6& status = 0
我必须处理0值......
此表单用于过滤我的任务。
这是我在控制器中操作的一部分:
if($request->query->has('user')) {
$category_id = $request->query->get('category');
$user_id = $request->query->get('user');
$status_id = $request->query->get('status');
// A little test to see if it works.
echo $category_id . '<br>' . $user_id . '<br>' . $status_id;
// I will pass these variables to a repository
$tasks = $em->getRepository('LanCrmBundle:Task')->findFiltered($category_id, $user_id, $status_id);
} else {
$tasks = $em->getRepository('LanCrmBundle:Task')->findAll();
}
我用这种方法创建了一个存储库:
public function findFiltered($category_id, $user_id, $status_id)
{
/**
* Get filtered tasks.
*
* Get only title, priority, created_at, category_id, user_id and status_id fields (optimization)
*
* Where field category_id = $category_id unless $category_id is smaller than 1 (not secure enough)
* Where field user_id = $user_id unless $user_id is smaller than 1 (not secure enough)
* Where field status_id = $status_id unless $status_id is smaller than 1 (not secure enough)
* Should I do these tests here or in the controller?
*/
}
如何进行此查询?你还有其他优雅的建议来解决这个问题吗?
答案 0 :(得分:0)
您可以尝试:
public function findFiltered($category_id, $user_id, $status_id)
{
$queryBuilder = $this->createQueryBuilder('t');
if(!empty($category_id) && is_numeric($category_id)) {
$queryBuilder->andWhere('t.category = :category')->setParameter('category', $category_id);
}
if(!empty($user_id) && is_numeric($user_id)) {
$queryBuilder->andWhere('t.user = :user')->setParameter('user', $user_id);
}
if(!empty($status_id) && is_numeric($status_id)) {
$queryBuilder->andWhere('t.status = :status')->setParameter('status', $status_id);
}
return $queryBuilder->getQuery()->getResult();
}