Question

我如何从中得到：

var props = new List<RoomProperties>();
props.Add(new RoomProperties(new[] {3, 4, 5}, new string[] {"AC", "WC"}));
props.Add(new RoomProperties(new[] {2}, new string[] {"AC", "TV"}));
props.Add(new RoomProperties(new[] {3}, new string[] {"Music", "Phone"}));

对此：

Key = 2, Values = ("AC", "TV") 
Key = 3, Values = ("AC", "WC","Music", "Phone" )
Key = 4, Values = ("AC", "WC") 
Key = 5, Values = ("AC", "WC")

使用props.props.SelectMany()我可以让键变平，但值与之无关。如果您有一个好主意如何以优雅的方式做到这一点我会很感激。基本上我希望每个ID连接房间属性，ID用这些数据唯一表示。

private class RoomProperties
{
    public readonly int[] RoomIds;
    public string[] Properties { get; private set; }

    public RoomProperties(int[] roomIds, string[] properties)
    {
        RoomIds = roomIds;
        Properties = properties;
    } 
}

Answer 1

您可以使用房间ID和房间属性将序列展平为匿名对象。然后按房间ID对这些对象进行分组，并从组中选择所有属性（我还添加了Distinct以避免重复的房间值）：

props.SelectMany(p => p.RoomIds.Select(id => new { id, p.Properties }))
     .GroupBy(x => x.id)
     .Select(g => new { 
         g.Key, 
         Values = g.SelectMany(x => x.Properties).Distinct() 
     });

将汇总数据投影到平坦数据

1 个答案: