Question

我有这个示例代码和nee打印输出，例如单独的第二个论点位置，我该怎么做？

def fun(a, b, c):
     d = locals()
     e = d
     print (e)
     print (locals())

fun(None, 2, None)

Answer 1

print(b) ......或者我不明白这个问题。

更新：如果您想知道参数的名称，可能需要使用名为inspect的标准模块。请尝试以下方法：

#!python3
import inspect

def fun(a, b, c):
     d = locals()
     e = d
     print (e)
     print (locals())

     # Here for observing from inside.
     argspec = inspect.getfullargspec(fun)
     print(argspec.args)
     for arg in argspec.args:
         print('argument', repr(arg), '=', repr(d[arg])) 

     # You can use indexing of the arg names if you like. Then the name
     # is used for looking in locals() -- here you have it in d.
     args = argspec.args
     print(d[args[0]])    
     print(d[args[1]])    
     print(d[args[2]])    

fun(None, 2, None)

# Here for observing from outside.
argspec = inspect.getfullargspec(fun)
print(argspec.args)

for n, arg in enumerate(argspec.args, 1):
    print('argument', n, 'is named', repr(arg))

你应该观察：

{'a': None, 'b': 2, 'c': None}
{'d': {...}, 'e': {...}, 'a': None, 'b': 2, 'c': None}
['a', 'b', 'c']
argument 'a' = None
argument 'b' = 2
argument 'c' = None
None
2
None
['a', 'b', 'c']
argument 1 is named 'a'
argument 2 is named 'b'
argument 3 is named 'c'

请参阅文档http://docs.python.org/3.3/library/inspect.html#inspect.getfullargspec

我如何打印位置参数

1 个答案: