我正在开发一个基于eclipse的Java应用程序。但我无法抓住异常。我想同时使用HSSF
和XSSF
阅读excel文件(.xlsx)。但是HSSF
正常工作,否则XSSF没有。这是我的代码。在wb = new XSSFWorkbook(pkg);
语句之后,程序计数转到finally语句。
提前谢谢。
try {
if (FileFormat == FILE_FORMAT_XLS) {
fs = new POIFSFileSystem(new FileInputStream(szFileName));
wb = new HSSFWorkbook(fs);
}
// This block does not work properly.
else if (FileFormat == FILE_FORMAT_XLSX) {
file = new File(szFileName);
if (file.exists() == false || file.isFile() == false || file.canRead() == false) {
throw new IOException(szFileName);
}
pkg = OPCPackage.open(file);
wb = new XSSFWorkbook(pkg); // **<- Here is the problem.**
}
if (wb != null) {
evaluator = wb.getCreationHelper().createFormulaEvaluator();
sheetNum = wb.getNumberOfSheets();
for (int i = 0; i < sheetNum; i++) {
for (Row row : wb.getSheetAt(i)) {
person ps = new person();
if (getPerson(row, ps) == true) {
list.add((Object) ps);
log.addLog(list.size() + " " + ps.getName() + ", " + ps.getHanName() + ", " + ps.getEnName() + ", " + ps.getBirthDay() + ", " + ps.getCellPhone() + ", " + ps.getID() + ", " + ps.getAddress());
} else {
log.addLog("total count = " + list.size());
ps = null;
break;
}
}
}
} else {
log.addLog("can not open workbook");
}
} catch (Exception e) {
e.printStackTrace();
}
finally {
if (wb != null) {
wb = null;
}
}
答案 0 :(得分:0)
程序是否在没有捕获异常的情况下转到finally
?
wb对象为null或将存在异常堆栈跟踪。
wb对象也必须是合适的类型。无论是HSSF还是XSSF。 尝试实例化xssfworkbook,如
XSSFWorkbook工作簿=新的XSSFWorkbook(szFileName);