Question

我对json相当新，我很难弄清楚如何解析特定的json响应。我在这个主题中搜索了很多，但我没有找到任何套件或适用于我的情况。因此，我知道它看起来像是重复的。

首先让我描述一下我的情景。

我有一个Mysql表

表格结构

mysql> describe faculty;
+-----------------------+-------------+------+-----+---------+-------+
| Field                 | Type        | Null | Key | Default | Extra |
+-----------------------+-------------+------+-----+---------+-------+
| faculty_id            | varchar(8)  | NO   | PRI | NULL    |       |
| faculty_name          | text        | NO   |     | NULL    |       |
| department_id         | varchar(8)  | YES  | MUL | NULL    |       |
| department_name       | text        | NO   |     | NULL    |       |
| profile_pic           | text        | NO   |     | NULL    |       |
| designation           | text        | NO   |     | NULL    |       |
| doj                   | date        | NO   |     | NULL    |       |
| email                 | text        | NO   |     | NULL    |       |
| highest_qualification | varchar(10) | YES  |     | NULL    |       |
| industrial_exp_yr     | smallint(6) | YES  |     | NULL    |       |
| industrial_exp_month  | smallint(6) | YES  |     | NULL    |       |
| teaching_exp_yr       | smallint(6) | YES  |     | NULL    |       |
| teaching_exp_month    | smallint(6) | YES  |     | NULL    |       |
| area_of_interest      | text        | NO   |     | NULL    |       |
| national_pub          | smallint(6) | YES  |     | NULL    |       |
| international_pub     | smallint(6) | YES  |     | NULL    |       |
+-----------------------+-------------+------+-----+---------+-------+
16 rows in set (0.01 sec)

我的JS：

 $("#up_dept").change(function() {
        var dept = $('#up_dept option:selected').text();
        $.ajax({
            url: "proc/get_flist.php",
            type: "POST",
            data: {
                dept: dept
            },
            dataType: "json",
            async: true,
            cache: false,
            success: function(response) {
                // Tried naive forloop 
                // JSON.Parse
               // Nothing worked so kept blank
            }
        });
    });

PHP

$fac = new Faculty();
$dept = trim($_POST["dept"]);
$facul_list = $fac->faculty_list($dept);
echo json_encode($facul_list);

faculty_list功能

function faculty_list($dept_name) {
        try {
            $db = new PDO(DB_CONN, DB_USER, DB_PASS);
            $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
            $db->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
            $query = "select * from faculty where department_name ='" . $dept_name . "';";
            $stmt = $db->query($query);
            if ($stmt->rowCount() > 0) {
                $list = $stmt->fetchAll();
                $db = null;
                return $list;
            } else {
                return "NULL";
            }
        } catch (PDOException $ex) {
            echo $ex->getMessage();

            //utils::log_error($ex -> getMessage());
        }
    }

[{"faculty_id":"fac_001","0":"fac_001","faculty_name":"Arnab Roy","1":"Arnab Roy","department_id":"dep_002","2":"dep_002","department_name":"Electrical Engineering","3":"Electrical Engineering","profile_pic":"card-arnab.png","4":"card-arnab.png","designation":"Asst. Prof","5":"Asst. Prof","doj":"2014-01-07","6":"2014-01-07","email":"arnab@gmail.com","7":"arnab@gmail.com","highest_qualification":"M.Tech","8":"M.Tech","industrial_exp_yr":0,"9":0,"industrial_exp_month":0,"10":0,"teaching_exp_yr":3,"11":3,"teaching_exp_month":0,"12":0,"area_of_interest":"CURCITS","13":"CURCITS","national_pub":0,"14":0,"international_pub":0,"15":0},{"faculty_id":"fac_002","0":"fac_002","faculty_name":"Utsav Banerjee","1":"Utsav Banerjee","department_id":"dep_002","2":"dep_002","department_name":"Electrical Engineering","3":"Electrical Engineering","profile_pic":"fac_002_ad-learning-centre.jpg","4":"fac_002_ad-learning-centre.jpg","designation":"Asst. Prof","5":"Asst. Prof","doj":"2014-02-09","6":"2014-02-09","email":"utsav@gmail.com","7":"utsav@gmail.com","highest_qualification":"M.Tech","8":"M.Tech","industrial_exp_yr":5,"9":5,"industrial_exp_month":0,"10":0,"teaching_exp_yr":0,"11":0,"teaching_exp_month":6,"12":6,"area_of_interest":"CIRCITS , BLOB ","13":"CIRCITS , BLOB ","national_pub":0,"14":0,"international_pub":3,"15":3}]

现在，我需要能够console.log响应的每个字段说，

response.faculty_id [0];

请帮我解决这个问题。我不太确定响应是否是有效的json。

Answer 1

response是一个数组，你需要循环它。

success: function(response) {
    $.each(response, function(index, data) {
      console.log(data.faculty_id);
    });
    // get the first one only
    console.log(response[0], response[0].faculty_id);
}

Answer 2

只需用

替换此行

return $list;

这一个

return json_encode($list);

你的问题应该解决了！

Answer 3

试试这个

var json_resp = jQuery.parseJSON（response）; 的console.log（json_resp [0] .faculty_id）

在Jquery中解析json_encode返回

3 个答案: