我可以将 FOO 放在哪里以最终产生真实效果?我玩哈希集(只对前2个值正确),conj和concat,但我知道我没有正确处理单元素与设置条件中的任何一个。
(defn mergeMatches [propertyMapList]
"Take a list of maps and merges them combining values into a set"
(reduce #(merge-with FOO %1 %2) {} propertyMapList))
(def in
(list
{:a 1}
{:a 2}
{:a 3}
{:b 4}
{:b 5}
{:b 6} ))
(def out
{ :a #{ 1 2 3}
:b #{ 4 5 6} })
; this should return true
(= (mergeMatches in) out)
最常用的处理方式是什么?
答案 0 :(得分:12)
这样做:
(let [set #(if (set? %) % #{%})]
#(clojure.set/union (set %) (set %2)))
更直接地重写示例(Alex):
(defn to-set [s]
(if (set? s) s #{s}))
(defn set-union [s1 s2]
(clojure.set/union (to-set s1) (to-set s2)))
(defn mergeMatches [propertyMapList]
(reduce #(merge-with set-union %1 %2) {} propertyMapList))
答案 1 :(得分:5)
我没有写这个,但是contributed @amitrathore Twitter上的{{3}}:
(defn kv [bag [k v]]
(update-in bag [k] conj v))
(defn mergeMatches [propertyMapList]
(reduce #(reduce kv %1 %2) {} propertyMapList))
答案 2 :(得分:4)
我不会使用merge-with,
(defn fnil [f not-found]
(fn [x y] (f (if (nil? x) not-found x) y)))
(defn conj-in [m map-entry]
(update-in m [(key map-entry)] (fnil conj #{}) (val map-entry)))
(defn merge-matches [property-map-list]
(reduce conj-in {} (apply concat property-map-list)))
user=> (merge-matches in)
{:b #{4 5 6}, :a #{1 2 3}}
fnil将很快成为核心的一部分,因此您可以忽略实现......但它只是创建了另一个可以处理nil参数的函数的版本。在这种情况下,conj会将#{}替换为nil。
因此,对于提供的地图列表中的每个键/值,减少连接到一个集合。
答案 3 :(得分:3)
@wmacgyver根据Twitter对multimaps提供的另一个解决方案:
(defn add
"Adds key-value pairs the multimap."
([mm k v]
(assoc mm k (conj (get mm k #{}) v)))
([mm k v & kvs]
(apply add (add mm k v) kvs)))
(defn mm-merge
"Merges the multimaps, taking the union of values."
[& mms]
(apply (partial merge-with union) mms))
(defn mergeMatches [property-map-list]
(reduce mm-merge (map #(add {} (key (first %)) (val (first %))) property-map-list)))
答案 4 :(得分:2)
不是很漂亮,但它确实有效。
(defn mergeMatches [propertyMapList]
(for [k (set (for [pp propertyMapList] (key (first pp))))]
{k (set (remove nil? (for [pp propertyMapList] (k pp))))}))
答案 5 :(得分:2)
这似乎有效:
(defn FOO [v1 v2]
(if (set? v1)
(apply hash-set v2 v1)
(hash-set v1 v2)))