Question

代码看起来像这样

public HttpResponseMessage PostUser(User user)
{
    if (ModelState.IsValid)
    {
        try
        {
            db.Users.Add(user);
            db.SaveChanges();
        }
        catch (MySqlException e)
        {
            ....
        }
    }
}

WebServer由于重复Key而返回500 Internal，但从未进入catch块。我想知道如何在上面的代码中捕获MySql异常。

ExceptionMessage: "Duplicate entry 'TEST2' for key 'IX_User'"
ExceptionType: "MySql.Data.MySqlClient.MySqlException"

StackTrace: 
MySql.Data.MySqlClient.MySqlStream.ReadPacket() 
MySql.Data.MySqlClient.NativeDriver.GetResult(Int32& affectedRow, Int64& insertedId) 
MySql.Data.MySqlClient.Driver.NextResult(Int32 statementId, Boolean force) 
MySql.Data.MySqlClient.MySqlDataReader.NextResult() 
MySql.Data.MySqlClient.MySqlCommand.ExecuteReader(CommandBehavior behavior) 
MySql.Data.Entity.EFMySqlCommand.ExecuteDbDataReader(CommandBehavior behavior) 
System.Data.Entity.Infrastructure.Interception.InternalDispatcher`1.Dispatch[TInterceptionContext,TResult](Func`1 operation, TInterceptionContext interceptionContext, Action`1 executing, Action`1 executed) 
System.Data.Entity.Infrastructure.Interception.DbCommandDispatcher.Reader(DbCommand command, DbCommandInterceptionContext interceptionContext) 
System.Data.Entity.Core.Mapping.Update.Internal.DynamicUpdateCommand.Execute(Dictionary`2 identifierValues, List`1 generatedValues) 
System.Data.Entity.Core.Mapping.Update.Internal.UpdateTranslator.Update()"

Answer 1

你可以通过 SQLException 来处理它：

// your class code

try{
// do your work
}catch(SQLExcepetipn e){
// handle it
}

没有MYSQL异常类。

无法捕获MySqlException [Entity Framework WebAPI]

1 个答案: