TypeError：无法调用null的方法'setTextValue'

Question

首先，是的，我在发布此问题之前搜索了网站并遵循了一些建议，但仍然得出了相同的结果。我还会告诉你，这段代码很旧，并且在2012年在facebook上工作。我不是开发/编码器。我知道一些PHP。从我在一些帖子上看到的内容，他们通过将js向下移动到close标签附近来实现它。现在这就是我的问题所在。此代码不使用任何头部或身体标签。所以，如果我能弄明白这一点，它可能会帮助我解决其他java问题。以下是我在Chrome开发工具中提供错误的代码。

    function recheck(what){
    var ajax = new Ajax();
    ajax.responseType = Ajax.JSON;
    ajax.ondone = function(data) {                          
        if(what=="energy"){
            if(data.timeLeft>60){
                numEnergySeconds = data.timeLeft 

                currEnergy = data.value;
                did('energy').setTextValue(currEnergy);
                if (currEnergy>=maxEnergy){
                    did('energyTime').setTextValue("");
                }
                energyCalled=false;//reset this
            } else {
                setTimeOut(recheck(what),data.timeLeft*1000);
            }                                   
        } else if(what=="stamina"){                             
            if(data.timeLeft>60){
                numStaminaSeconds = data.timeLeft; 

                currStamina = data.value;
                did('stamina').setTextValue(currStamina);
                if (currStamina>=maxStamina){
                    did('staminaTime').setTextValue("");
                }
                staminaCalled=false;//reset this
            } else {
                setTimeOut(recheck(what),data.timeLeft*1000);
            }       
        } else if(what=="health"){                              
            if(data.timeLeft>60){
                numHealthSeconds = data.timeLeft; 

                currHealth = data.value;
                did('health').setTextValue(currHealth);
                if (currHealth>=maxHealth){
                    did('healthTime').setTextValue("");
                }
                healthCalled=false;//reset this
            } else {
                setTimeOut(recheck(what),data.timeLeft*1000);
            }       
        }
    }
    ajax.onerror = function() {
        recheck(what)
    }
    ajax.post("<?echo $src?>resources/recheck.php", {"what": what});                            
}

function updateLevels() {
    if (currStamina<maxStamina) {
        numStaminaSeconds--;
        if (numStaminaSeconds<0  && !staminaCalled) {
            staminaCalled=true;
            did('staminaTime').setTextValue("...")

            recheck('stamina'); 

        } else if(!staminaCalled  && currStamina<maxStamina){
                did('staminaTime').setTextValue(getLevelText(numStaminaSeconds));
        }
    } else {
        did('staminaTime').setTextValue("")
     Uncaught TypeError: Cannot call method 'setTextValue' of null
    }
        if (currEnergy<maxEnergy) {
        numEnergySeconds--;
        if (numEnergySeconds<0 && !energyCalled) {
            energyCalled=true;
            did('energyTime').setTextValue("...")                               

            recheck('energy');                  

        } else if (!energyCalled && currEnergy<maxEnergy) {
            did('energyTime').setTextValue(getLevelText(numEnergySeconds));
        }
    } else {
        did('energyTime').setTextValue("");

    }

    if (currHealth<maxHealth) {
        numHealthSeconds--;
        if (numHealthSeconds<0 && !healthCalled) {
            healthCalled=true;
            did('healthTime').setTextValue("...")                                   

            recheck('health');                  

        } else if (!healthCalled && currHealth<maxHealth) {
            did('healthTime').setTextValue(getLevelText(numHealthSeconds));
        }
    } else {
        did('healthTime').setTextValue("");
    }
}

function getLevelText( val ) {
    var numMinutes = Math.floor(val / 60);
    var numSeconds = val % 60;
    if (numSeconds<10) numSeconds = "0"+numSeconds;
    return ("("+numMinutes+":"+numSeconds+")");
}

我放入了面板中出现错误的位置。我知道代码可能不是很漂亮或最新，但我愿意接受如何解决这个问题的建议，而不需要雇用编码器来重写文件中的js。