Question

我试图检查一个表中的值与另一个表中的值，然后更新第一个表中的字段，当它们不匹配但我不能让代码工作。

到目前为止我尝试了什么;

DoCmd.RunSQL "UPDATE Issues SET Message='There is an issue at or before the sex code Field' WHERE Issues.[Sex Code] = Ref.[Sex Code] AND Ref.[Sex Code] Is Null));"

DoCmd.RunSQL "UPDATE Issues SET Message = 'There is an issue at or before the Sex Code field' LEFT JOIN Ref ON Issues.[Sex Code] = Ref.[Sex Code] WHERE ((Ref.[Sex Code]) Is Null);"

DoCmd.RunSQL "SELECT Issues.[Sex Code] FROM Issues LEFT JOIN Ref ON Issues.[Sex Code] = Ref.[Sex Code] WHERE Ref.[Sex Code] Is Null UPDATE Issues SET Message='There is an issue at or before the Sex Code Field'"

Answer 1

使用您的上述想法，您需要的是以下内容，但是您确定只想加入性别代码而没有其他字段（如姓名，ID＃等）？

UPDATE Issues LEFT JOIN Ref ON Issues.[Sex Code] = Ref.[Sex Code] SET Issues.Message = 'There is an issue at or before the Sex Code field'
WHERE (((Ref.[Sex Code]) Is Null));

要允许多个错误，您只需附加到“消息”字段，如下所示（保留任何先前的消息）：

UPDATE Issues LEFT JOIN Ref ON Issues.[Sex Code] = Ref.[Sex Code] 
SET Issues.Message = [Issues]![Message] & 'The Sex Code field is Null' & '; '
WHERE (((Ref.[Sex Code]) Is Null));

根据不匹配的值更新字段

1 个答案: