Question

所以我有listview加载来自mysql的数据.. 它加载ID（可见性：消失），名称，价格，..每个列表我想要它，当我长时间点击和上下文菜单显示，我点击项目或项目输出它将获得项目的ID并发送到下一个活动..但我的只获得listview的第一个ID ..请帮助我

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.all_products);

    // Hashmap for ListView
    productsList = new ArrayList<HashMap<String, String>>();

    // Loading products in Background Thread
    new LoadAllProducts().execute();

    // Get listview
    ListView lv = getListView();
    registerForContextMenu(lv);

@Override
public void onCreateContextMenu(ContextMenu menu, View v,
        ContextMenuInfo menuInfo) {

    super.onCreateContextMenu(menu, v, menuInfo);
    menu.setHeaderTitle("Barang Masuk/Keluar");
    menu.add(0, v.getId(), 0, "Masuk");
    menu.add(0, v.getId(), 0, "Keluar");
}

@Override
public boolean onContextItemSelected(MenuItem item) {

    if (item.getTitle() == "Masuk") {
         String pid = ((TextView) findViewById(R.id.pid)).getText()
         .toString();

        // Starting new intent
        Intent in = new Intent(getApplicationContext(),
                galian_barang_masuk.class);
        // sending pid to next activity
        in.putExtra(TAG_PID, pid);

        // starting new activity and expecting some response back
        startActivityForResult(in, 100);

    } else if (item.getTitle() == "Keluar") {
         String pid = ((TextView) findViewById(R.id.pid)).getText()
         .toString();

        // Starting new intent
        Intent in = new Intent(getApplicationContext(),
                galian_barang_keluar.class);
        // sending pid to next activity
        in.putExtra(TAG_PID, pid);

        // starting new activity and expecting some response back
        startActivityForResult(in, 100);
    } else {
        return false;
    }
    return true;
}

所以，当我从listview点击“pasir”然后上下文菜单出现.. 它转到listview“tanah”的第一个数据

http://imageshack.com/a/img835/2201/jrth.jpg

http://imageshack.com/a/img600/7562/ftzl.jpg

如果我使用直接点击listview onitem click ..使用此代码

lv.setOnItemClickListener(new OnItemClickListener() {

     @Override
     public void onItemClick(AdapterView<?> parent, View view,
     int position, long id) {
     String pid = ((TextView) view.findViewById(R.id.pid)).getText()
     .toString();

     Intent in = new Intent(getApplicationContext(),
     galian_barang_masuk.class);
     in.putExtra(TAG_PID, pid);

     startActivityForResult(in, 100);

     }
     });

但是当我使用上下文时出现错误..不知道如何..

编辑：我想它..我制作新的textview ..我通过长按加载ID并将其保存到新的textview

lv.setOnItemLongClickListener(new OnItemLongClickListener() {

        @Override
        public boolean onItemLongClick(AdapterView<?> parent, View view,
                int pos, long id) {
            // getting values from selected ListItem
            String pid = ((TextView) view.findViewById(R.id.pid)).getText()
                    .toString();
            x = (TextView) findViewById(R.id.x);
            x.setText(pid);

            return false;
        }
    });

之后在onContextItemSelected中我将in.putExtra(TAG_PID, pid)更改为in.putExtra(TAG_PID, x.getText().toString());新的textview，用于收集我长按的每个listitem ID ..

Answer 1

您可以使用AdapterContextMenuInfo从上下文菜单中获取所选列表项。例如，如果您有一个绑定到ListView的字符串列表，您将获得所选项目，如下所示：

@Override
public boolean onContextItemSelected(MenuItem item)
{
        AdapterView.AdapterContextMenuInfo info =
            (AdapterView.AdapterContextMenuInfo)item.getMenuInfo();
        String listItem = list.get(info.position);
                    //do something with the list item

}

Answer 2

findViewById（R.id.pid），列表中的每一行都有一个具有相同id的视图。所以结果可以是随机的（不确定它是否总是选择第一场比赛）。在这些情况下，您可以尝试使用自定义适配器，该适配器可将所需值设置为视图的标记。即在渲染列表行时，使用setTag方法为textview设置所需的值，然后使用getTag检索它。

从listview获取文本并发送到上下文菜单

2 个答案: