Question

我有2个圈子，都有触控听众。有时候一个圆圈在舞台上与另一个圆圈重叠，我想要触发两个听众，但是椋鸟只触发前面的圆圈。

我该怎么办？

我的代码

circle1.addEventListener(TouchEvent.TOUCH, touched1)
circle2.addEventListener(TouchEvent.TOUCH, touched2)
function touched1(e:TouchEvent):void{
  trace("hi1")
}
function touched2(e:TouchEvent):void{
  trace("hi2")
}

Answer 1

没有两个单独的侦听器，只有一个父对象的侦听器。并在此父对象中添加这两个圆圈。要检测触摸的目标，请使用e.target.name，如下所示：

var parentClip:Sprite = new Sprite();
parentClip.x = 150; // x position
parentClip.y = 150; // y position
parentClip.name = "parentClip"; //This is not required in your case

parentClip.addChild(circle1);
parentClip.addChild(circle2);

parentClip.addEventListener(TouchEvent.TOUCH, onTouched);

function onTouched(e:TouchEvent):void
{
     trace("circles parent is touched");
     trace("Hit: " + e.currentTarget.name);
     trace("Hit: " + e.target.name);
}

Answer 2

可能会检测圈子是否接触。试试这个：

circle1.addEventListener(TouchEvent.TOUCH, touched1)
circle2.addEventListener(TouchEvent.TOUCH, touched2)

function touched1(e:TouchEvent=null):void
{
    trace("hi1");

    if (circle1.getBounds(circle1.parent).intersects(circle2.getBounds(circle2.parent)) == true)
    {
        touched2();
    }
}

function touched2(e:TouchEvent=null):void
{
    trace("hi2")

    if (circle2.getBounds(circle2.parent).intersects(circle1.getBounds(circle1.parent)) == true)
    {
        touched1();
    }
}

Starling - 在另一个下面获得触摸事件

2 个答案: