Question

当我想从一个表到另一个表获取其值时，但是当我想要编辑值时，它会将新值添加到tbl_ItemDetails。我只需要更新现有的行。

CREATE TRIGGER trigger_UpdateItemDetails ON tbl_PurchaseDetails

FOR INSERT AS

DECLARE @PurchaseID VARCHAR(20)

DECLARE @Quantity INT

DECLARE @WarehouseID VARCHAR(20)

SELECT @PurchaseID=(PurchaseID) FROM INSERTED

SELECT @Quantity=(ItemQuantity) FROM INSERTED

SELECT @WarehouseID=(WarehouseID) FROM INSERTED

INSERT INTO 

tbl_ItemDetails

(PurchaseID,Quantity,WarehouseID)

VALUES

(@PurchaseID,@Quantity,@WarehouseID)

Answer 1

让我从这开始：你永远不应该编写无法处理集合的触发器。

CREATE TRIGGER trigger_UpdateItemDetails ON tbl_PurchaseDetails
FOR INSERT AS

UPDATE itm
SET  PurchaseID=i.PurchaseID
    ,Quantity=i.ItemQuantity
    ,WarehouseID=i.WarehouseID
FROM INSERTED i
INNER JOIN tbl_ItemDetails itm ON i.???=itm.???
--I have no idea what your join clause should be as I don't know your data structure

创建触发器以将记录从表插入到另一个表中

1 个答案: