我不知道如果标题是好的,但无论如何,我想知道我们是否可以在将重复项与另一个表相加之后添加表的总和,如下例所示:
表A:
Date BL Client Design Ref1 Ref2 Ref3 Qte
14/01/2013 13011401 A VT VT1 JAUNE XL 3
14/01/2013 13011402 B VT VT2 GRIS L 62
16/01/2013 13011601 D VT VT1 GRIS L 10
19/01/2013 13011903 F VT VT2 JAUNE L 15
表B:
Date BL Client Design Ref1 Ref2 Ref3 Qte
14/01/2013 13011401 A VT VT1 JAUNE XL 3
14/01/2013 13011402 B VT VT2 GRIS L 100
16/01/2013 13011601 D VT VT1 GRIS L 10
19/01/2013 13011903 F VT VT2 JAUNE L 15
结果:
Date BL Client Design Ref1 Ref2 Ref3 Qte
14/01/2013 13011401 A VT VT1 JAUNE XL 6
14/01/2013 13011402 B VT VT2 GRIS L 162
16/01/2013 13011601 D VT VT1 GRIS L 20
19/01/2013 13011903 F VT VT2 JAUNE L 30
条件是( Client,Design,Ref1,Ref2,Ref3 )在两个表中应该相同!
答案 0 :(得分:0)
您可以尝试使用JOINS
SELECT
TableA.Date,
TableA.BL,
TableA.Client,
TableA.Design,
TableA.Ref1,
TableA.Ref2,
TableA.Ref3,
TableA.Qte + TableB.Qte As Qte
FROM
TableA
JOIN
TableB ON TableA.Client = TableB.Client
AND TableA.Design = TableB.Design
AND TableA.Ref1 = TableB.Ref1
AND TableA.Ref2 = TableB.Ref2
AND TableA.Ref3 = TableB.Ref3;
答案 1 :(得分:0)
我想这就是你想要的
select t.Date,t.BL,t.Client,t.Design,t.Ref1,t.Ref2,t.Ref3, t.Qte+t1.Qte as qte
from table1 t inner join table2 t1
on t.client=t1.client and
t.design=t1.design and
t.ref1=t1.ref1 and
t.ref2=t1.ref2 and
t.ref3=t1.ref3;
答案 2 :(得分:0)
这是另一种方法。它可以扩展为处理两个以上的表。
SELECT Date, BL, Client, Design, Ref1, Ref2, Ref3, SUM(Qte) Qte
FROM (
SELECT Date, BL, Client, Design, Ref1, Ref2, Ref3, Qte FROM TableA
UNION ALL
SELECT Date, BL, Client, Design, Ref1, Ref2, Ref3, Qte FROM TableB
) t
GROUP BY Date, BL, Client, Design, Ref1, Ref2, Ref3, Qte