Question

UPDATE emr_cwagreich.patient_medication a
INNER JOIN
(
    SELECT emr_cwagreich.patient_medication_archive.id AS id,
        emr_cwagreich.patient_medication_archive.drug_syn_id AS drug_syn_id, 
        pk.NDC10 AS ndc10, 
        pk.NDC11 AS ndc11, 
        pk.PackageID AS package_id, 
        pd.ProductID AS product_id, 
        pd.MarketedProductID AS marketed_product_id,
        pgns.GenericNameLong AS medication_name
    FROM emr_cwagreich.patient_medication_archive
    JOIN ep_api.CORE_GENDRUG_SYNONYM cgs ON emr_cwagreich.patient_medication_archive.drug_syn_id = cgs.DRUG_SYN_ID
    JOIN ep_api.NDC_PKG_PRODUCT npp ON cgs.DRUG_SYN_ID = npp.DRUG_SYN_ID
    JOIN ep_alchemy.package pk ON npp.CORE_10 = pk.NDC10
    JOIN ep_alchemy.product pd ON pk.ProductID = pd.ProductID
    JOIN ep_alchemy.product_generic_name_stub pgns ON pd.ProductID = pgns.ProductID
    GROUP BY medication_name
    ORDER BY COUNT(pgns.GenericNameLong) DESC
    LIMIT 1
) b ON a.id = b.id
SET a.ndc10 = b.ndc10,
    a.ndc11 = b.ndc11,
    a.package_id = b.package_id,
    a.product_id = b.product_id,
    a.marketed_product_id = b.marketed_product_id,
    a.medication_name = b.medication_name
WHERE (b.drug_syn_id <> "" AND b.drug_syn_id IS NOT NULL)
AND
(a.product_id = "" OR a.product_id IS NULL)
AND 
a.id = 17221

上面的查询有语法错误。我的数据库管理工具（HeidiSQL）告诉我第2行附近有语法错误，但我不能为我的生活弄清楚它在哪里......

任何获得此项目的人都会获得巨大的道具。

致Fabio：错误是（逐字逐句）

SQL Error (1064): You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use near
'UPDATE emr_cwagreich.patient_medication a INNER JOIN (SELECT emr_cwagrei' at line 2

我把它缩小到内连接语句中的子选择（就此而言，我通过删除连接减少了这个子选择的复杂性）。这是：

SELECT pma.id AS id,
    pma.drug_syn_id AS drug_syn_id, 
    pk.NDC10 AS ndc10, 
    pk.NDC11 AS ndc11, 
    pk.PackageID AS package_id, 
    pk.ProductID AS product_id,
    pgns.GenericNameLong AS medication_name
FROM emr_cwagreich.patient_medication_archive pma
JOIN ep_api.CORE_GENDRUG_SYNONYM cgs ON pma.drug_syn_id = cgs.DRUG_SYN_ID
JOIN ep_api.NDC_PKG_PRODUCT npp ON cgs.DRUG_SYN_ID = npp.DRUG_SYN_ID
JOIN ep_alchemy.package pk ON npp.CORE_10 = pk.NDC10
JOIN ep_alchemy.product_generic_name_stub pgns ON pk.ProductID = pgns.ProductID
GROUP BY medication_name
ORDER BY COUNT(pgns.GenericNameLong) DESC
LIMIT 1

此查询未返回语法错误。它只需要很长时间（即使我已经在外键上放置了索引......）

Answer 1

看起来您的SQL语句布局不正确。

您不能在emr_cwagreich.patient_medication语句之后将表a别名为UPDATE，而是在SET语句之后需要稍后。尝试重新排列您的查询，如下所示：

UPDATE  a
  SET   a.ndc10 = b.ndc10,
        a.ndc11 = b.ndc11,
        a.package_id = b.package_id,
        a.product_id = b.product_id,
        a.marketed_product_id = b.marketed_product_id,
        a.medication_name = b.medication_name
  FROM  emr_cwagreich.patient_medication a
    INNER JOIN
...

请注意在FROM之后添加SET语句，然后您可以为更新表添加别名并加入其他表。

Answer 2

要正确调试：

在Update中只抛出SELECT，并检查SELECT是否返回了正确的结果，可能是你的错误。我在查询开头没有看到错误，UPDATE emr_cwagreich.patient_medication a INNER JOIN ( ...似乎是正确的。

这是SELECT中的字段吗？我从来没有见过emr_cwagreich.patient_medication_archive.id为什么你有三个规格项？

更新

使用新选择尝试更新，并检查是否有效：

UPDATE emr_cwagreich.patient_medication a
INNER JOIN
(
    SELECT pma.id AS id,
    pma.drug_syn_id AS drug_syn_id, 
    pk.NDC10 AS ndc10, 
    pk.NDC11 AS ndc11, 
    pk.PackageID AS package_id, 
    pk.ProductID AS product_id,
    pgns.GenericNameLong AS medication_name
    FROM emr_cwagreich.patient_medication_archive pma
    JOIN ep_api.CORE_GENDRUG_SYNONYM cgs ON pma.drug_syn_id = cgs.DRUG_SYN_ID
    JOIN ep_api.NDC_PKG_PRODUCT npp ON cgs.DRUG_SYN_ID = npp.DRUG_SYN_ID
    JOIN ep_alchemy.package pk ON npp.CORE_10 = pk.NDC10
    JOIN ep_alchemy.product_generic_name_stub pgns ON pk.ProductID = pgns.ProductID
    GROUP BY medication_name
    ORDER BY COUNT(pgns.GenericNameLong) DESC
    LIMIT 1
) b ON a.id = b.id
SET a.ndc10 = b.ndc10,
    a.ndc11 = b.ndc11,
    a.package_id = b.package_id,
    a.product_id = b.product_id,
    a.marketed_product_id = b.marketed_product_id,
    a.medication_name = b.medication_name
WHERE (b.drug_syn_id <> "" AND b.drug_syn_id IS NOT NULL)
AND
(a.product_id = "" OR a.product_id IS NULL)
AND 
a.id = 17221

复杂查询中的语法错误

2 个答案:

更新