Question

我正在尝试将设备令牌传递给我的服务器，但面临一些问题，即我的数据库中的所有内容都可以存储为空，我不会在这里做错。

-(void)application:(UIApplication *)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken
   { 
       const char* data = [deviceToken bytes];
       NSMutableString * token = [NSMutableString string];

       for (int i = 0; i < [deviceToken length]; i++) {
            [token appendFormat:@"%02.2hhX", data[i]];
       }

       NSString *urlString = [NSString stringWithFormat:@"http://localhost/pushnofiy/insert.php?token=%@",token];

       NSURL *url = [[NSURL alloc] initWithString:urlString];
       NSLog(@"token %@",urlString);
       NSURLRequest *urlRequest = [NSURLRequest requestWithURL:url];
       NSLog(@"request %@ ",urlRequest);

       NSData *urlData;
       NSURLResponse *response;
       urlData = [NSURLConnection sendSynchronousRequest:urlRequest returningResponse:&response error:nil];
    }

如果我打印显示设备令牌的urlString，但我不知道它为什么不插入数据库。

代码

<?php

    mysql_connect(localhost,$username);
    @mysql_select_db($database) or die("Unable to find Database");*/
    include "db.php";

    $token =$_GET["token"];

    $query = "INSERT INTO notifi (token) VALUES('$token')";

    mysql_query($query) or die (mysql_error("error"));
    mysql_close();
 ?>

我不知道出现了什么问题，任何人都告诉我哪里做错了。

感谢。

Answer 1

最好添加错误恢复机制（如果请求失败，您将丢失令牌）并使用异步请求（在后台发送令牌）

在你的AppDelegate.m中：

- (void)application:(UIApplication*)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData*)deviceToken
{
    NSString * token = [NSString stringWithFormat:@"%@", deviceToken];
    //Format token as you need:
    token = [token stringByReplacingOccurrencesOfString:@" " withString:@""];
    token = [token stringByReplacingOccurrencesOfString:@">" withString:@""];
    token = [token stringByReplacingOccurrencesOfString:@"<" withString:@""];

    [[NSUserDefaults standardUserDefaults] setObject:token forKey:@"apnsToken"]; //save token to resend it if request fails
    [[NSUserDefaults standardUserDefaults] setBool:NO forKey:@"apnsTokenSentSuccessfully"]; // set flag for request status
    [DataUpdater sendUserToken]; //send token
}

发送令牌创建新类（或使用现有类）：的 DataUpdater.h

#import <Foundation/Foundation.h> @interface DataUpdater : NSObject + (void)sendUserToken; @end

<强> DataUpdater.m

#import "DataUpdater.h" @implementation DataUpdater + (void)sendUserToken { if ([[NSUserDefaults standardUserDefaults] boolForKey:@"apnsTokenSentSuccessfully"]) { NSLog(@"apnsTokenSentSuccessfully already"); return; } NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://myhost.com/filecreate.php?token=%@",[[NSUserDefaults standardUserDefaults] objectForKey:@"apnsToken"]]]; //set here your URL NSURLRequest *urlRequest = [NSURLRequest requestWithURL:url]; NSOperationQueue *queue = [[NSOperationQueue alloc] init]; [NSURLConnection sendAsynchronousRequest:urlRequest queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) { if (error == nil) { [[NSUserDefaults standardUserDefaults] setBool:YES forKey:@"apnsTokenSentSuccessfully"]; NSLog(@"Token is being sent successfully"); //you can check server response here if you need } }]; } @end

然后你可以调用[DataUpdater sendUserToken];在出现互联网连接的控制器中，或定期或在 - （void）viewDidLoad或 - （void）viewWillAppear 方法

我的建议： 1）我使用AFNetworking发送异步请求并检查服务器JSON响应 2）有时最好使用Parse等服务来处理推送通知

设备令牌传递给服务器空

1 个答案: