在每个项目后插入逗号,但不是最后一个项目

时间:2014-02-25 00:32:40

标签: java string joptionpane

我在java中有一个程序,当你输入一个句子时,程序会告诉你有多少回文单词并输出单词。但是,当我输出单词时,我似乎无法在每次输出后得到逗号。例如,如果我输入“Abba正在运行到雷达”它输出有2个回文并且回文是“ Abba雷达”。然而,我希望它输出回文“阿巴,雷达”。无论我怎么做,我都可以得到“Abba Radar”或“Abba,Radar”。任何帮助将不胜感激。

代码

package strings;

import javax.swing.*;

public class Palindrome2 {

public static void main(String[] args) {
    String word = JOptionPane.showInputDialog("Words that are the same forwards and backwards are called palindromes.\nThis program determines if the words are palindromes.\n\nEnter a sentence(do not include a punctuation mark):");

    String newWord[] = word.split(" ");
    String palindromeWords = "";
    int count = 0;

    for (int i = 0; i < newWord.length; i++) {
        String result = new StringBuffer(newWord[i]).reverse().toString();
        if (newWord[i].toLowerCase().equals(result.toLowerCase())) {
            count++;
            palindromeWords = palindromeWords + " " + newWord[i];
        }
    }
    JOptionPane.showMessageDialog(null, "There are " + count + " palindromes in this sentence");
    if (count != 0) {
        JOptionPane.showMessageDialog(null, "The palindromes are:\n" + palindromeWords);
    } else {
        JOptionPane.showMessageDialog(null, "There isn't any palindromes.");
    }
}
}

3 个答案:

答案 0 :(得分:1)

只需将您的代码修改为:

for (int i = 0; i < newWord.length; i++) {
    String result = new StringBuffer(newWord[i]).reverse().toString();
    if (newWord[i].toLowerCase().equals(result.toLowerCase())) {
        count++;
        palindromeWords = palindromeWords + newWord[i] + ",";
    }
}

for循环后,substring删除最后一个逗号:

palindromeWords = palindromeWords.substring(0,palindromeWords.length()-1);

答案 1 :(得分:0)

代码也可以是

    if (newWord[i].toLowerCase().equals(result.toLowerCase())) {
        count++;
        if (count > 1)
        {
            palindromeWords += ", ";
        }
        palindromeWords += newWord[i];
    }

答案 2 :(得分:0)

在发现第一个单词之后,逗号位于新单词之前...

public static void main(String[] args) {
    String word = JOptionPane.showInputDialog("Words that are the same forwards and backwards are called palindromes.\nThis program determines if the words are palindromes.\n\nEnter a sentence(do not include a punctuation mark):");

    String newWord[] = word.split(" ");
    StringBuffer palindromeWords = new StringBuffer();
    int count = 0;

    for (int i = 0; i < newWord.length; i++) {
        String result = new StringBuffer(newWord[i]).reverse().toString();
         if (newWord[i].toLowerCase().equals(result.toLowerCase())) {
            if (count > 0) {
               palindromeWords.append(",");
            }
            palindromeWords.append(newWord[i]);
            count++;
        }
    }
JOptionPane.showMessageDialog(null, "There are " + count + " palindromes in this sentence");
    if (count != 0) {
        JOptionPane.showMessageDialog(null, "The palindromes are:\n" + palindromeWords.toString());
    } else {
        JOptionPane.showMessageDialog(null, "There isn't any palindromes.");
    }
}

所以我将palindromewords更改为StringBuffer并在追加操作后移动count ++。希望这有帮助!