我在使用WPF的visual stdio 2010中使用带有emgucv的kinect!我想从kinect获取帧并使用emgucv将其转换为灰度我有这个!
void myKinect_ColorFrameReady(object sender,ColorImageFrameReadyEventArgs e) {
using (ColorImageFrame colorFrame = e.OpenColorImageFrame())
{
if (colorFrame == null) return;
if (colorData == null)
colorData = new byte[colorFrame.PixelDataLength];
colorFrame.CopyPixelDataTo(colorData);
if (colorImageBitmap == null)
{
this.colorImageBitmap = new WriteableBitmap(
colorFrame.Width,
colorFrame.Height,
96, // DpiX
96, // DpiY
PixelFormats.Bgr32,
null);
}
this.colorImageBitmap.WritePixels(
new Int32Rect(0, 0, colorFrame.Width, colorFrame.Height),
colorData, // video data
colorFrame.Width * colorFrame.BytesPerPixel, // stride,
0 // offset into the array - start at 0
);
Image<Gray, Byte> My_Image = new Image<Gray, byte>(BitmapFromSource(colorImageBitmap));
kinectVideo.Source = ToBitmapSource(My_Image);
}
}
private System.Drawing.Bitmap BitmapFromWriteableBitmap(WriteableBitmap writeBmp)
{
System.Drawing.Bitmap bmp;
using (MemoryStream outStream = new MemoryStream())
{
BitmapEncoder enc = new BmpBitmapEncoder();
enc.Frames.Add(BitmapFrame.Create((BitmapSource)writeBmp));
enc.Save(outStream);
bmp = new System.Drawing.Bitmap(outStream);
}
return bmp;
}
private System.Drawing.Bitmap BitmapFromSource(BitmapSource bitmapsource)
{
System.Drawing.Bitmap bitmap;
using (MemoryStream outStream = new MemoryStream())
{
BitmapEncoder enc = new BmpBitmapEncoder();
enc.Frames.Add(BitmapFrame.Create(bitmapsource));
enc.Save(outStream);
bitmap = new System.Drawing.Bitmap(outStream);
}
return bitmap;
}
[DllImport("gdi32")]
private static extern int DeleteObject(IntPtr o);
public static BitmapSource ToBitmapSource(IImage image)
{
using (System.Drawing.Bitmap source = image.Bitmap)
{
IntPtr ptr = source.GetHbitmap(); //obtain the Hbitmap
BitmapSource bs = System.Windows.Interop.Imaging.CreateBitmapSourceFromHBitmap(
ptr,
IntPtr.Zero,
Int32Rect.Empty,
System.Windows.Media.Imaging.BitmapSizeOptions.FromEmptyOptions());
DeleteObject(ptr); //release the HBitmap
return bs;
}
}