[XmlRoot("Quote")]
public class Quote
{
[XmlElement("Insurance")]
public InsuranceDetails InsDetails { get; set; }
[XmlElement("Payment")]
public PaymentDetails PayDetails { get; set; }
}
public class InsuranceDetails : IXmlSerializable
{
[XmlElement(ElementName = "Details1")]
public string Details1 { get; set; }
public void ReadXml(XmlReader reader)
{
reader.ReadStartElement("Insurance");
Details1 = reader.ReadElementString("Details1");
reader.ReadEndElement();
}
public void WriteXml(XmlWriter writer)
{
// do write suff
}
}
public class PaymentDetails
{
[XmlElement(ElementName = "Details1")]
public string Details1 { get; set; }
}
鉴于此示例,使用XmlSerializer将我的字符串反序列化为QuoteObject,PaymentDetails未成功反序列化,返回null对象,因为它似乎应该具有IXmlDeserializable。它只适用于首先解析PaymentDetails的情况。这是XmlSerializer的一些预期行为吗?
using (TextReader read = new StringReader(xml))
{
var serializer = new XmlSerializer(typeof(Quote));
return (Quote)serializer.Deserialize(read);
}
答案 0 :(得分:1)
这些是我修改的ReadXml
和WriteXml
:
public void ReadXml(XmlReader reader)
{
reader.MoveToContent();
var empty=reader.IsEmptyElement;
reader.ReadStartElement();
if(!empty){
Details1=reader.ReadElementString("Details1");
reader.ReadEndElement();
}
}
public void WriteXml(XmlWriter writer)
{
var str=string.IsNullOrWhiteSpace(Details1)?"":Details1;
writer.WriteElementString("Details1",str);
}
以下是序列化和反序列化函数:
public static string Serialize<T>(T t)
{
var xmlser=new XmlSerializer(typeof(T));
XmlWriterSettings settings = new XmlWriterSettings();
using(StringWriter textWriter = new StringWriter()) {
using(XmlWriter xmlWriter = XmlWriter.Create(textWriter, settings)) {
xmlser.Serialize(xmlWriter, t);
}
return textWriter.ToString();
}
}
public static T Deserialize<T>(string xml)
{
if(string.IsNullOrEmpty(xml)) {
return default(T);
}
XmlSerializer serializer = new XmlSerializer(typeof(T));
XmlReaderSettings settings = new XmlReaderSettings();
using(StringReader textReader = new StringReader(xml)) {
using(XmlReader xmlReader = XmlReader.Create(textReader, settings)) {
return (T) serializer.Deserialize(xmlReader);
}
}
}
序列化测试:
var q=new Quote();
q.PayDetails = new PaymentDetails{Details1="Payment Details 1"};
q.InsDetails=new InsuranceDetails{Details1="Insurance Details 1"};
str = Serialize<Quote>(q);
给出(str):
<?xml version="1.0" encoding="utf-16"?>
<Quote xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Payment>
<Details1>Payment Details 1</Details1>
</Payment>
<Insurance>
<Details1>Insurance Details 1</Details1>
</Insurance>
</Quote>
反序列化测试:
var dq=Deserialize<Quote>(str);
Console.WriteLine(dq.PaymentDetails.Detail1);//gives "Payment Details 1"
Console.WriteLine(dq.InsuranceDetails.Detail1);//gives "Insurance Details 1"
PS: - Serialize代码是从另一个SO答案中逐字复制的。我学会了如何使用StringWriter
序列化为字符串。
答案 1 :(得分:1)
首先,您不必在任何类中实现IXmlSerializable
。其次,您不提供xml
变量的内容。如果您手动创建,它可能包含错误/错误。
我使用以下代码来测试你的类:
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
namespace XmlDeSerialize
{
[XmlRoot("Quote")]
public class Quote
{
[XmlElement("Insurance")]
public InsuranceDetails InsDetails { get; set; }
[XmlElement("Payment")]
public PaymentDetails PayDetails { get; set; }
}
public class InsuranceDetails
{
[XmlElement(ElementName = "Details1")]
public string Details1 { get; set; }
}
public class PaymentDetails
{
[XmlElement(ElementName = "Details1")]
public string Details1 { get; set; }
}
class Program
{
static void Main(string[] args)
{
var qin = new Quote
{
InsDetails = new InsuranceDetails { Details1 = "insurance details text" },
PayDetails = new PaymentDetails { Details1 = "payment details text" },
};
string xml;
using (var stream = new MemoryStream())
{
var serializer = new XmlSerializer(typeof(Quote));
serializer.Serialize(stream, qin);
stream.Position = 0;
using (var sr = new StreamReader(stream))
{
xml = sr.ReadToEnd();
}
}
Quote qout;
using (TextReader read = new StringReader(xml))
{
var deserializer = new XmlSerializer(typeof(Quote));
var obj = deserializer.Deserialize(read);
qout = (Quote)obj;
}
Console.WriteLine("InsDetails.Details1='{0}'", qout.InsDetails.Details1);
Console.WriteLine("PayDetails.Details1='{0}'", qout.PayDetails.Details1);
}
}
}
序列化后xml
的值:
<?xml version="1.0"?>
<Quote xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Insurance>
<Details1>insurance details text</Details1>
</Insurance>
<Payment>
<Details1>payment details text</Details1>
</Payment>
</Quote>
我收到的控制台输出:
InsDetails.Details1='insurance details text'
PayDetails.Details1='payment details text'
亲自尝试代码,看看它是否适合您。很明显,对于我来说,你没有为反序列化提供有效的XML内容,或者你的问题中未提供的代码的其他部分应该受到责备。