我在for循环中进行异步调用,我知道响应是异步的,但我怎么能以相同的顺序得到我的响应。这是我的代码:
setInterval(function () {
callback = function (response)
{
var temp2 = '';
var str = "";
test = [];
console.log('STATUS: ' + response.statusCode);
response.setEncoding('utf8');
response.on('data', function (chunk)
{
str += chunk;
});
response.on('end', function ()
{
console.log("end found");
temp2 = JSON.parse(str);
for (var i in temp2['build'])
{
test.push(temp2['build'][i]['id']);
var req3 = http.request({
host: host, // here only the domain name
auth: auth,
port: 8111,
path: '/httpAuth/app/rest/builds/id:' + test[i] + '/statistics/', // the rest of the url with parameters if needed
method: 'GET', // do GET
headers: { "Accept": "application/json" }
}, callback2);
req3.end();
}
});
}
var req4 = http.request(options4, callback);
req4.end();
callback2 = function (response) {
//console.log('STATUS: ' + response.statusCode);
//console.log('HEADERS: ' + JSON.stringify(response.headers));
response.setEncoding('utf8');
var str2 = "";
response.on('data', function (chunk) {
str2 += chunk;
});
response.on('end', function () {
points.push(parseInt(JSON.parse(str2)["property"][2]["value"]));
});
j++;
if (j == test.length) {
var sumTotal = 0;
var sumThree = 0;
var status = '';
for (var i in points) {
sumTotal += points[i];
}
var averageTotal = parseInt(Math.round(sumTotal / points.length));
for (var i = 0; i < 3; i++) {
sumThree += points[i];
}
var averageThree = parseInt(Math.round(sumThree / 3));
/*if(averageThree>averageTotal)
{
status='warning';
}
else
{
status='ok';
}*/
console.log('average: ' + averageThree + ' average 100 ' + averageTotal + ' status ' + status);
//send_event('speed', {current: averageThree/*, status: status*/, last: averageTotal});
j = 0;
points = [];
}
}
}, 15 * 1000);
所以我的问题是我怎么能确定我的回答'点'总是有相同的顺序。我已经尝试将var i发送到回调函数但无法使其工作
编辑: 改变了格式。 第一个回调的输出:
{
"count":100,
"nextHref":"/httpAuth/app/rest/builds/?locator=buildType:bt2,count:100,status:SUCCESS,start:100",
"build":[
{
"id":17469,
"number":"5075",
"status":"SUCCESS",
"buildTypeId":"bt2",
"startDate":"20140224T183152+0100",
"href":"/httpAuth/app/rest/builds/id:17469",
"webUrl":"http://x.x.x.x:8111/viewLog.html?buildId=17469&buildTypeId=bt2"
},
{
"id":17464,
"number":"5074",
"status":"SUCCESS",
"buildTypeId":"bt2",
"startDate":"20140224T165758+0100",
"href":"/httpAuth/app/rest/builds/id:17464",
"webUrl":"http://x.x.x.x:8111/viewLog.html?buildId=17464&buildTypeId=bt2"
},
{
"id":17461,
"number":"5073",
"status":"SUCCESS",
"buildTypeId":"bt2",
"startDate":"20140224T161852+0100",
"href":"/httpAuth/app/rest/builds/id:17461",
"webUrl":"http://x.x.x.x:8111/viewLog.html?buildId=17461&buildTypeId=bt2"
},
此输出包含100个项目。从这个输出中我获取id号并使用这个id数组发出一个新请求。这个新的回调给了我构建持续时间,但问题是因为这是异步发生的,我得到的响应不是来自最新版本,而是来自第一个响应。所以我的问题是如何才能以正确的顺序获得这些构建速度数组
答案 0 :(得分:1)
不建议在for循环中使用匿名函数。
最好的方法(对我来说),就是使用异步库。
一个简单的例子来回答你的问题:
var objectList = [
{"name":"Doe", "firstname":"John", "position":1},
{"name":"Foo", "firstname":"Bar", "position":2},
{"name":"Gates", "firstname":"Bill", "position":3},
{"name":"Jobs", "firstname":"Steve", "position":4},
];
var arr = [];
async.each(objectList, function(person, callback) {
arr.push(person); // async.each is asynchronous, so at the end, the order will be bad
}, function(err) {
async.sortBy(arr, function(p, callback) { // Reorder
callback(err, p.position);
}, function(err, results) {
callback(null, results); // Send the result
});
});
此示例适用于您的问题。