Question

我想使用确认弹出窗口删除我的项目，因此这是我的删除操作：

public function deleteAction()
{       
    $id = (int) $this->params()->fromRoute('id', 0);
    $article = $this->getObjectManager()->find('\Application\Entity\Article', $id);
    if ($this->zfcUserAuthentication()->hasIdentity()) {

    if ($this->request->isPost()) 
    {

         $this->getObjectManager()->remove($article);
         $this->getObjectManager()->flush();

         return $this->redirect()->toRoute('blog');
    }
    }
    else
    {
        return $this->redirect()->toRoute('user');
    }

    return new ViewModel(array('article' => $article));
}

这是我的博客视图，其中我有删除链接：

<a href="<?php echo $this->url('delete', array('action'=>'delete', 'id' => $articles->getId())) ?>" class="btn btn-default btn-lg" onclick="if (confirm('Are you sure?')) { document.location = this.href; } return false;" id="dialog">Delete Article</a>
                <?php endif;?>
                      <script type="text/javascript">
                      $(function() {
                        $( "#dialog:ui-dialog" ).dialog( "destroy" );

                        $( "#dialog-confirm" ).dialog({
                            resizable: false,
                            height:140,
                            modal: true,
                            buttons: {
                                "Are you sure": function() {
                                                        document.form.submit();
                                    $( this ).dialog( "close" );
                                },
                                Cancel: function() {
                                    $( this ).dialog( "close" );
                                }
                            }
                        });
                    });
                      </script>

问题是，当我按下链接时，它被重定向到delete.phtml视图，我想要的是在确认弹出窗口时删除该项目。

所以，如果有人有任何解决方案，我将非常感激:)

Answer 1

您可以使用confirm方法。

if (window.confirm('Are you sure you want to delete?'))
{
    window.location = "<?php echo $this->url('delete', array('action'=>'delete', 'id' => $articles->getId())) ?>"
}
else
{
    // do nothing
}

如果你想使用jQuery UI对话框，

                        buttons: {
                            "Are you sure": function() {
                                window.location = "<?php echo $this->url('delete', array('action'=>'delete', 'id' => $articles->getId())) ?>"
                                $( this ).dialog( "close" );
                            },
                            Cancel: function() {
                                $( this ).dialog( "close" );
                            }
                        }

Answer 2

我知道这是一个老问题，但它对我很有帮助。所以我认为必须有其他人也在寻找答案。所以我在这里怎么做..

转到http://adriancallaghan.co.uk/jquery-confirmation-box-thickbox/
下载并将javascript保存到您的＆＃39; js＆＃39;文件夹（我放入＆＃39; js / azza / deletebox.js＆＃39;）

然后在视图* .phtml文件中添加指向该文件的链接

$this->inlineScript()->prependFile($this->basePath('js/azza/deletebox.js'));

然后按如下方式编辑你的href

<a href="<?php echo $this->url('article', array('action' => 'delete', 
'id' => $article->getId())); ?>" 
title="<?php echo "Delete ".$article->getNama(); ?>"    
id="dialog-confirm" class="dialog-confirm">Delete</a>

设置＆＃39; id＆＃39;非常重要和＆＃39;班级＆＃39; as＆＃34; dialog-confirm＆＃34;触发javascript函数
您还需要Jquery和Jquery-UI才能使此脚本正常工作

那是......

如何在确认弹出窗口中使用zend delete动作？

2 个答案: