我正在尝试加密某些内容并对其进行解密。我没有解密 - 我得到了上面的例外。我尝试改变ctLength和ptLength,但无济于事。我究竟做错了什么? 我正在尝试加密:0 0 0 0 0 0 0 0
private Cipher encrypt(byte[] input)
{
try
{
SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");
// encryption pass
cipher.init(Cipher.ENCRYPT_MODE, key);
byte[] cipherText = new byte[cipher.getOutputSize(input.length)];
int ctLength = cipher.update(input, 0, input.length, cipherText, 0);
ctLength += cipher.doFinal(cipherText, ctLength);
FileOutputStream fs = new FileOutputStream(savedScoresFileName);
fs.write(cipherText);
return cipher;
}
catch (Exception e)
{
Log.e("encrtypt", "Exception", e);
}
return null;
}
private String decrypt()
{
try
{
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");
SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");
byte[] cipherText = new byte[32];
FileInputStream fl = new FileInputStream(savedScoresFileName);
fl.read(cipherText);
cipher.init(Cipher.DECRYPT_MODE, key);
byte[] plainText = new byte[cipher.getOutputSize(32)];
int ptLength = cipher.update(cipherText, 0, 32, plainText, 0);
ptLength += cipher.doFinal(plainText, ptLength);
return new String(plainText).substring(0, ptLength);
}
catch (Exception e)
{
Log.e("decrypt", "Exception", e);
}
return null;
}
此代码是从this复制而来的。
答案 0 :(得分:3)
您的代码存在许多问题,但您的问题是由文件读取代码和执行加密和解密的奇怪方法引起的。
请勿使用update()
方法,只需使用doFinal()
并更正您的文件写入/阅读代码。例如。你的解密方法应该类似于:
try {
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");
SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");
// Here you need to accurately and correctly read your file into a byte
// array. Either Google for a decent solution (there are many out there)
// or use an existing implementation, such as Apache Commons commons-io.
// Your existing effort is buggy and doesn't close its resources.
byte[] cipherText = FileUtils.readFileToByteArray(new File(savedScoresFileName));
cipher.init(Cipher.DECRYPT_MODE, key);
// Just one call to doFinal
byte[] plainText = cipher.doFinal(cipherText);
// Note: don't do this. If you create a string from a byte array,
// PLEASE pass a charset otherwise your result is platform dependent.
return new String(plainText);
} catch (Exception e) {
e.printStackTrace();
}