在case语句erlang中跳过else条件

Question

我有一个列表（AllData），我正在迭代，根据sepc文档条件获取一些元素。保持空元组{}或仅ok会导致我的列表出现问题，而且我不想在内部案例语句的else（_->）块中向我的NewList插入任何内容。

我们可以跳过else（_-＆gt;）条件吗？

以下是我的示例代码：

lists:foldl(fun(X , {Counter, NewList}) ->
        case X:number() of 
          {Aa, Bb} ->
            case  X:id() == Aa of 
                true ->
                    //Aa matched 
                     {Counter+1, [X:items()|NewList] }  
                _->
                    %% I want to skip the code that goes here in inner case statement.
                    %% Doing anything here showing a wrong output. 
                    %% Keeping empty tuple with counter changing my output like 
                         {Counter+1, [[]|NewList] }  
                    %% I don't have to do anything here at all.

                end;
            _->
                 %% Execute some other code and append to J
                 {Counter+1, [X:items()|NewList] }  
         end
    end,{0, []}, AllData).

Answer 1

只需返回Counter和NewList：

{Counter, NewList }