我正在使用CodeIgnitor Framework在网站上工作。
问题与CodeIgniter,Jquery Ajax,表单提交和文件上载
有关 <form method="post" action="" id="upload_file" enctype="multipart/form-data">
<div id="inner2" style="display:none">
<div class="trainingcontent" style="height:400px;">
<div class="chaptername" >
<p>Chapter Name</p>
<input type="text" id="cname" name="cname" class="awesome-text-box" />
<input type="hidden" id="training_id" name="training_id" />
</div>
<div class="trainingurl">
<p>Training Video</p>
<input type="text" id="video_url" name="video_url" class="awesome-text-box" placeholder="Paste your video URL here..."/>
</div>
<div class="uploadpdf">
<p>Upload PDF</p>
<a href="#"><div class="uploadbutton">
<div class="uploadtext"> <input type="file" name="userfile" id="userfile" size="20" />UPLOAD PDF </div>
</div></a>
</div>
</form>
function abc(){
var training_id = $('#training_id').attr('value');
var cname = $('#cname').attr('value');
var video_url = $('#video_url').attr('value');
$.ajax({
type: "POST",
url: "../chapters/create",
data: "training_id="+training_id+"&cname="+cname+"&video_url="+video_url,
success: function(returned_html){
echo returned_html;
}
});
}//end of function abc
如何将输入类型文件数据传递给控制器?
我尝试了各种方法但没有任何效果。
答案 0 :(得分:5)
我在codeigniter
中使用JS的formData对象创建了类似的功能示例代码:
function abc(){
// create a FormData Object using your form dom element
var form = new FormData(document.getElementById('upload_file'));
//append files
var file = document.getElementById('userfile').files[0];
if (file) {
form.append('userfile', file);
}
//call ajax
$.ajax({
url: "../chapters/create",
type: 'POST',
data: form,
cache: false,
contentType: false, //must, tell jQuery not to process the data
processData: false, //must, tell jQuery not to set contentType
success: function(data) {
console.log(data);
},
complete: function(XMLHttpRequest) {
var data = XMLHttpRequest.responseText;
console.log(data);
},
error: function() {
alert("ERROR");
}
}).done(function() {
console.log('Done');
}).fail(function() {
alert("fail!");
});
}