Question

我正在尝试在像这样的列上应用运行公式。我尝试了很多我仍然无法做到这一点.Plz任何人都有想法使用oracle sql做到这一点，

EMP NO  SAL DEDUCTION BALANCE
1       10  5          10-5=5
1       10  2          5-2=3
1       15  2          3-2=1
1       21  1          1-1=0

我使用了滞后函数，但它返回了与上面单元格相同的值。

Answer 1

虽然业务需求对我来说仍然是一个谜，但这是一种方法（我已经添加了一个列来引入行的排序）：

with employees as (
  select 1 as rn, 1 as emp_no,10 as sal,5 as deduction, '10-5=5' as balance from dual union all 
  select 2 as rn, 1 as emp_no,10 as sal,2 as deduction, '5-2=3' as balance from dual union all 
  select 3 as rn, 1 as emp_no,15 as sal,2 as deduction, '3-2=1' as balance from dual union all 
  select 4 as rn, 1 as emp_no,21 as sal,1 as deduction, '1-1=0' as balance from dual )
select v1.*, 
  v1.sal - v1.aggr_deduction as remaining_sal_current_sal,
  v1.first_sal - v1.aggr_deduction as remaining_sal_first_sal 
from (
select rn,
       emp_no, 
       sal, 
       deduction,
       balance,
       sum(deduction) over (partition by emp_no order by rn) as aggr_deduction,
       (select sal from employees e1 where rn = 1 ) as first_sal
from employees
) v1
order by rn

SQL Fiddle

Answer 2

您需要一个排序字段才能正确区分。

我引入了一个增量字段来模拟一些排序。我认为不同的员工没有不同的扣减。否则，您可以按EMP_NO进行分区。

如果我正确理解了你的需要，试试这个：

CREATE TABLE T
(SORT_KEY   NUMBER,
 EMP_NO     NUMBER,
 SAL        NUMBER,
 DEDUCTION  NUMBER);

INSERT INTO T VALUES(1, 1, 10, 5);
INSERT INTO T VALUES(2, 1, 10, 2);
INSERT INTO T VALUES(3, 1, 15, 2);
INSERT INTO T VALUES(4, 1, 21, 1);

COMMIT;

SELECT SORT_KEY, SAL,
       ABS(V) AS DEDUCTION,
       SUM(V) OVER(ORDER BY SORT_KEY) AS BALANCE
FROM (SELECT SORT_KEY, SAL,
             CASE WHEN LAG(DEDUCTION, 1) OVER(ORDER BY SORT_KEY) IS NULL
                  THEN SAL - DEDUCTION
                  ELSE - DEDUCTION END AS V
      FROM t
      ORDER BY SORT_KEY)
ORDER BY SORT_KEY;

SORT_KEY   SAL   DEDUCTION  BALANCE
--------   --    ---------  -------
       1   10    5          5
       2   10    2          3
       3   15    2          1
       4   21    1          0

DROP TABLE T PURGE;

通过EMP_NO进行分区（如果这是你想要的）：

INSERT INTO T VALUES(5, 2, 10, 5);
INSERT INTO T VALUES(6, 2, 10, 2);
INSERT INTO T VALUES(7, 2, 15, 2);
INSERT INTO T VALUES(8, 2, 21, 1);

COMMIT;

SELECT SORT_KEY, EMP_NO, SAL,
       ABS(V) AS DEDUCTION,
       SUM(V) OVER(PARTITION BY EMP_NO ORDER BY SORT_KEY) AS BALANCE
FROM (SELECT SORT_KEY, EMP_NO, SAL,
             CASE WHEN LAG(DEDUCTION, 1) OVER(PARTITION BY EMP_NO ORDER BY SORT_KEY) IS NULL
                  THEN SAL - DEDUCTION
                  ELSE - DEDUCTION END AS V
      FROM t
      ORDER BY SORT_KEY)
ORDER BY EMP_NO, SORT_KEY;

oracle sql在查询中使用上面的单元格计算值

2 个答案: