Question

我有一个json输入，简化版本是：

{
"result": {
    "status": 1,
    "items": [
        {
            "name": "TF_WEAPON_EXAMPLE",
            "defindex": 0,
            "craft_material_type": "weapon",
            "used_by_classes": [
                "Scout",
                "Pyro"
            ]
        },
        {
            "name": "TF_WEAPON_BOTTLE",
            "defindex": 1,
            "craft_material_type": "weapon",
            "used_by_classes": [
                "Demoman"
            ]
        },
        {
            "name": "Paint Can 5",
            "defindex": 5031,
            "craft_material_type": "tool",
            "used_by_classes": [

            ]
        }
    ]
}
}

我想获取每个“used_by_classes”的值，所以我尝试使用：

$schema_items = $json['result']['items'];
foreach($schema_item['used_by_classes'] as $class)
{
   echo $class;
}

这导致我Invalid query: Unknown column 'class' in 'field list'

我该怎么办？如果可以的话，分享一些代码。

谢谢！

Answer 1

您的代码中存在错误拼写错误

$schema_items = $json['result']['items'];
foreach($schema_item['used_by_classes'] as $class)
      //^ here it should be $schema_items
{
   echo $class;
}

Answer 2

这是你应该在这里做的

foreach($item in $schema_items){
    echo $item["used_by_classes"]
}

Answer 3

首先，您在JSON中拥有Object not Array。所以你应该这样做：

$schema_items = $json->result->items;
foreach($schema_items as $class)
{
    print_r($class->used_by_classes); // your array with "used_by_classes" values
}

Answer 4

我通过替换$key => $class解决了这个问题，如下所示：

foreach($schema_item['used_by_classes'] as $key => $class)
{
   echo $class;
}

Answer 5

以下是解析它的方法：

<强> PHP：

$json = json_decode($data, true);
$result = $json['result'];
$schema_items = $result['items'];

foreach($schema_items as $class)
{
    foreach($class['used_by_classes'] as $SubClass)
    {
        echo $SubClass."<br />";
    }
}

<强>输出：

Scout
Pyro
Demoman

DEMO

PHP：从JSON文件获取数据

5 个答案: