Question

好的，我有三种不同类型的用户（开发人员，设计人员和雇主），他们都拥有不同的数据库表。我已经成功开发了一个脚本，可以使用UNION从三个用户表中的任何一个表登录用户。但是我现在已经在注册时引入了电子邮件验证，所以我需要测试'确认'字段（在每个表中）是否具有值'1'来处理成功登录（如果值为0，则用户不会能够登录）。

    public function email_confirmed($email) {

        $query = $this->db->prepare("SELECT 
            COUNT(developers.id) FROM " . DB_NAME . ".developers WHERE developers.email=  ? AND developers.confirmed = ? 
            UNION SELECT COUNT(designers.id) FROM " . DB_NAME . ".designers WHERE designers.email = ? AND designers.confirmed = ? 
            UNION SELECT COUNT(employers.id) FROM " . DB_NAME . ".employers WHERE employers.email = ? AND employers.confirmed = ?
            ");
        $query->bindValue(1, $email);
        $query->bindValue(2, 1);
        $query->bindValue(3, $email);
        $query->bindValue(4, 1);
        $query->bindValue(5, $email);
        $query->bindValue(6, 1);

        try{

            $query->execute();
            $rows = $query->fetchColumn();

            if($rows == 1){
                return true;
            }else{
                return false;
            }

        } catch(PDOException $e){
            die($e->getMessage());
        }
    }

目前（使用下面的功能），只有开发人员才能登录。如果您尝试使用设计人员或雇主帐户登录，则会显示以下错误。任何想法为什么会发生这种情况？

 if ($users->email_confirmed($email) === false) {
        $errors[] = 'Sorry, but you need to activate your account. Please check your emails.';
    } else // carry on logging in user

Answer 1

这是您的查询：

SELECT COUNT(developers.id)
FROM " . DB_NAME . ".developers
WHERE developers.email=  ? AND developers.confirmed = ? 
UNION
SELECT COUNT(designers.id)
FROM " . DB_NAME . ".designers
WHERE designers.email = ? AND designers.confirmed = ? 
UNION
SELECT COUNT(employers.id)
FROM " . DB_NAME . ".employers
WHERE employers.email = ? AND employers.confirmed = ?

获取三行，然后删除重复项，并任意排序。然后，您将从其中一行读取值（计数）。

采取你正在采取的方法，我认为你想要：

select COUNT(*)
from ((select 1
       from " . DB_NAME . ".developers
       where developers.email=  ? AND developers.confirmed = ? 
      ) union all 
      (select 1
       from  " . DB_NAME . ".designers
       where designers.email = ? AND designers.confirmed = ? 
      ) union all
      (select 1
       from " . DB_NAME . ".employers
       where employers.email = ? AND employers.confirmed = ?
      )
     ) t

PDO UNION函数仅处理第一个SELECT语句

1 个答案: