我正试图通过rails AR查询界面实现“真正的”左连接,但无法找到如何这样做,需要急切加载......
我可以通过AR界面生成以下查询
scope :user_search, lambda {|user_id| includes(:trip_item).where("trip_items.user_id = ? OR trip_items.user_id IS NULL", user_id).order("trip_items.updated_at desc") }
apartments = Apartment.where(:location_id => near_by_locations.map(&:id).uniq)
apartments = apartments.where.not(:id => exclude) unless exclude == nil
apartments = apartments.where("apartments.updated_at >= :date", :date => 20.days.ago)
apartments = apartments.where("apartments.price >= ?", search.min_price)
apartments = apartments.where("apartments.price <= ?", search.max_price) unless search.max_price == nil
apartments = apartments.where("apartments.rooms >= ?", search.min_rooms)
apartments = apartments.where("apartments.rooms <= ?", search.max_rooms) unless search.max_rooms == nil
apartments = apartments.order("apartments.updated_at DESC").user_search(user_id)
SELECT * FROM "apartments"
LEFT OUTER JOIN "trip_items" ON "trip_items"."apartment_id" = "apartments"."id"
WHERE "apartments"."location_id" IN (1, 8, 11, 13, 12, 7) AND ("apartments"."id" NOT IN (27, 8))
AND (apartments.updated_at >= '2014-02-03 19:02:11.609227') AND (apartments.price >= 100)
AND (apartments.price <= 5000) AND (apartments.rooms >= 1.0)
AND (trip_items.user_id = 1 OR trip_items.user_id IS NULL)
ORDER BY apartments.updated_at DESC, trip_items.updated_at desc
但我需要以下内容,以返回空的左表记录:
SELECT * FROM "apartments"
LEFT OUTER JOIN "trip_items" ON "trip_items"."apartment_id" = "apartments"."id" AND trip_items.user_id = 1
WHERE "apartments"."location_id" IN (1, 8, 11, 13, 12, 7) AND ("apartments"."id" NOT IN (27, 8))
AND (apartments.updated_at >= '2014-02-03 19:02:11.609227') AND (apartments.price >= 100)
AND (apartments.price <= 5000) AND (apartments.rooms >= 1.0)
ORDER BY apartments.updated_at DESC, trip_items.updated_at desc
帮助表示赞赏......
答案 0 :(得分:0)
首先,为什么这条线会出现两次?
apartments = apartments.where("apartments.rooms <= ?", search.max_rooms) unless search.max_rooms == nil
无论如何使用这个
apartments = Apartment.where(:location_id => near_by_locations.map(&:id).uniq)
apartments = apartments.where.not(:id => exclude) unless exclude == nil
apartments = apartments.where("apartments.updated_at >= :date", :date => 20.days.ago)
apartments = apartments.where("apartments.price >= ?", search.min_price)
apartments = apartments.where("apartments.price <= ?", search.max_price) unless search.max_price == nil
apartments = apartments.where("apartments.rooms >= ?", search.min_rooms)
apartments = apartments.includes(:trip_items).where("trip_items.user_id = ?", user_id)
apartments = apartments.order("apartments.updated_at DESC ,trip_items.updated_at desc")
这将生成以下内容
SELECT * FROM "apartments"
WHERE "apartments"."location_id" IN (1, 8, 11, 13, 12, 7)
AND ("apartments"."id" NOT IN (27, 8))
AND (apartments.updated_at >= '2014-02-03 19:02:11.609227')
AND (apartments.price >= 100)
AND (apartments.price <= 5000) AND (apartments.rooms >= 1.0)
LEFT OUTER JOIN "trip_items" ON "trip_items"."apartment_id" = "apartments"."id" AND trip_items.user_id = 1
ORDER BY apartments.updated_at DESC, trip_items.updated_at desc