使用Paypal登录API集成成功的Paypal登录将预期数据返回为空

时间:2014-02-23 13:37:36

标签: php wordpress paypal openid

我有一个无法解决的问题。我正在尝试在wordpress上创建一个应用程序,当用户访问页面时,它将自动要求用户使用paypal帐户登录和验证。成功登录后,我想显示配置文件详细信息(首先仅用于测试),然后再次对其进行编码以用于预期用途。但是,我使用下面的代码,当我成功登录时,进行身份验证并重定向到redirect_url(意味着登录和验证过程正确完成),print_r的预期配置文件详细信息为空

<?php
/* Paypal app details */
$client_id = 'xxxx';    // paypal client id
$client_secret = 'xxx'; // client secret
$scopes = 'email profile';  //e.g. openid email profile https://uri.paypal.com/services/paypalattributes
$app_return_url = 'http://website.ccc/verify/';  // Redirect url
$nonce = time() . rand();

$code = $_REQUEST["code"];

if(empty($code)) {
    #IF the code paramater is not available, load the auth url.
    $state = md5(uniqid(rand(), TRUE)); // CSRF protection
    $paypal_auth_url = "https://www.paypal.com/webapps/auth/protocol/openidconnect/v1/authorize?"
            ."client_id=".$client_id
            ."&response_type=code"
            ."&scope=".$scopes
            ."&nonce=".$nonce
            ."&state=".$state
            ."&redirect_uri=".urlencode($app_return_url);

    header("Location: $paypal_auth_url");     
}else{
    /* GET Access TOKEN */
    $token_url = "https://www.paypal.com/webapps/auth/protocol/openidconnect/v1/tokenservice";    
    $postvals = "client_id=".$client_id
            ."&client_secret=".$client_secret
            ."&grant_type=authorization_code"
            ."&code=".$code;


    $ch = curl_init($token_url);
    $options = array(
                CURLOPT_POST => 1,
                CURLOPT_VERBOSE => 1,
                CURLOPT_POSTFIELDS => $postvals,
                CURLOPT_RETURNTRANSFER => 1,
                CURLOPT_SSLVERSION => 3
    );
    curl_setopt_array( $ch, $options );
    $response = curl_exec($ch);
    curl_close($ch);
    $atoken = json_decode($response);

    /* GET PROFILE DETAILS */
    $profile_url = "https://www.paypal.com/webapps/auth/protocol/openidconnect/v1/userinfo?"
            ."schema=openid"
            ."access_token=".$atoken->access_token;

    $ch = curl_init($profile_url);
    $options = array(
                CURLOPT_RETURNTRANSFER => 1,
                CURLOPT_SSLVERSION => 3
    );
    curl_setopt_array( $ch, $options );
    $response = curl_exec($ch);
    curl_close($ch);
    $profile= json_decode($response,true);  // PROFILE DETAILs in Array format


    /* View the Profile Details */

    echo "<pre>";
    print_r($profile);
    echo "</pre>";
}

?>

你能帮我解决这个问题吗?

1 个答案:

答案 0 :(得分:2)

你好朋友只需添加'&amp;'在访问令牌之前,

$ profile_url =“https://www.paypal.com/webapps/auth/protocol/openidconnect/v1/userinfo?”             “模式= OpenID的”             “**&安培; ** =的access_token” $ atoken-&GT;的access_token;