Question

如何将值$fbAppPath放入下面的PHP语句中？

<? print json_encode(array(array('text' => 'Become A Fan', 'href' => '$fbAppPath'))); ?>

Answer 1

您无法在单引号字符串中获取变量。 PHP会在出现时完全解释所有单引号字符串。（除了逃避单引号）

使用单引号获取变量的唯一方法是打破它们：

$foo = 'variable';
echo 'single-quoted-string-'.$foo.'-more-single-quoted-string';

Answer 2

或

<? print json_encode(array(array('text' => 'Become A Fan', 'href' => "more text ${fbAppPath} more text"))); ?>

如果要将变量值嵌入字符串中。在这种情况下，双引号很重要。

Answer 3

<? print json_encode(array(array('text' => 'Become A Fan', 'href' => $fbAppPath))); ?>

Answer 4

您不需要围绕已经是字符串的变量的引号。

'I am a string, because I am surrounded by quotes';

$string = 'I am a string, because I am surrounded by quotes';
if (is_string($string)) {
    echo 'Yes, the variable $string is a string, because it contains a string';
}

$anotherString = $string;
if (is_string($anotherString)) {
    echo 'The variable $anotherString is a string as well, because it contains a string as well';
}

$notWhatYouExpect = '$string';
echo $notWhatYouExpect;  // outputs the word '$string'

如何在单引号之间获取PHP变量？

4 个答案: