Question

我的数据库中有一个整数列，我希望得到它的值。使用query（）方法，getType（）返回3（字符串类型），getInt（）返回的数字范围为19-21

    String[] columns = {EpisodeEntry.EPISODE_ID, EpisodeEntry.TITLE, 
        EpisodeEntry.DESCRIPTION, EpisodeEntry.PUB_DATE,
        EpisodeEntry.DURATION, EpisodeEntry.LISTENED, 
        EpisodeEntry.CURRENT_TIME};

    Cursor cursor = database.query(EpisodeEntry.TABLE_NAME, columns,
        EpisodeEntry.DIRECTORY + " = \"" + directory + "\"",
            null, null, null, null);
    Log.d("sw9", "DB CURRENT TIME TYPE: " +
        cursor.getType(cursor.getColumnIndex(EpisodeEntry.CURRENT_TIME)));

使用rawQuery（）方法，游标返回1（整数类型），getInt（）返回正确的数字。

    Cursor cursor = database.rawQuery("SELECT * FROM episode WHERE directory = '"
        + directory + "'", null);
    Log.d("sw9", "DB CURRENT TIME TYPE: " +
        cursor.getType(cursor.getColumnIndex(EpisodeEntry.CURRENT_TIME)));

rawQuery（）方法是正确的，但我不知道为什么query（）方法不正确。有人能说清楚这个吗？

我最好使用rawQuery（）来避免这样的问题吗？问题是我的错（很可能）还是Androids错（不太可能）？

编辑：嗯所以我把它隔离到* vs命名列：

返回错误值“14”：

Cursor cursor = database.rawQuery("SELECT " + EpisodeEntry.EPISODE_ID + ", " +
            EpisodeEntry.TITLE + ", " +
            EpisodeEntry.DESCRIPTION + ", " + EpisodeEntry.PUB_DATE + ", " +
            EpisodeEntry.DURATION + ", " + EpisodeEntry.LISTENED + ", " +
            EpisodeEntry.CURRENT_TIME + " FROM episode WHERE directory = \""
            + directory + "\"", null);

返回正确的值：

Cursor cursor = database.rawQuery("SELECT * FROM episode WHERE directory = \""
            + directory + "\"", null);

架构：

private static final String SQL_CREATE_EPISODE =
        "CREATE TABLE " + EpisodeEntry.TABLE_NAME + " (" +
                EpisodeEntry.EPISODE_ID + " INTEGER PRIMARY KEY AUTOINCREMENT, " +
                EpisodeEntry.TITLE + TEXT_TYPE + COMMA_SEP +
                EpisodeEntry.DESCRIPTION + TEXT_TYPE + COMMA_SEP +
                EpisodeEntry.ENCLOSURE + TEXT_TYPE + " UNIQUE" + COMMA_SEP +
                EpisodeEntry.PUB_DATE + TEXT_TYPE + COMMA_SEP +
                EpisodeEntry.DURATION + TEXT_TYPE + COMMA_SEP +
                EpisodeEntry.GUID + TEXT_TYPE + COMMA_SEP +
                EpisodeEntry.DIRECTORY + TEXT_TYPE + COMMA_SEP +
                EpisodeEntry.LISTENED + " INTEGER" + COMMA_SEP +
                EpisodeEntry.CURRENT_TIME + " INTEGER" +
                ");";

SQLite Cursor选择特定的列返回所有字符串类型vs Select *返回正确的类型（String，Integer等）

0 个答案: