我正在上课。我应该创建Conway的生命游戏的简单版本。我在使用布尔值数组与使用BitSet之间进行了一些实验。我最终创建了这个小测试:
每次为BitSet和布尔数组运行测试后,bitset的平均值约为6ms,布尔数组的平均值约为1300ms。所以我的问题是,使用布尔值使用布尔值时,究竟是什么造成了巨大的开销呢?我预计会有所不同,但不是那么激烈。
以下是代码:
Life.java - 主要类
public class Life
{
private final int WIDTH = 100;
private final int HEIGHT = 100;
private Board board;
public static void main(String[] args)
{
new Life();
}
public Life()
{
board = createBoard();
// populate board with random data
Random random = new Random();
for (int j = 0; j < board.length(); j++)
{
boolean b = random.nextBoolean();
board.set(j, b);
}
random = null;
System.gc();
System.out.println("Starting test...");
long startTime = System.currentTimeMillis();
for (int i = 0; i < 10_000; i++)
{
Board tempBoard = createBoard();
for (int j = 0; j < board.length(); j++)
{
byte count = getNeighborCount(j);
boolean value = board.get(j);
boolean next = value ? count >= 2 && count <= 3 : count == 3;
tempBoard.set(j, next);
}
board = tempBoard;
}
long endTime = System.currentTimeMillis();
System.out.format("Took %d ms", endTime - startTime);
}
public Board createBoard()
{
return new ArrayBoard(WIDTH * HEIGHT);
//return new BitBoard(WIDTH * HEIGHT);
}
public byte getNeighborCount(int index)
{
byte count = 0;
if (getRelative(index, -1, -1)) count++;
if (getRelative(index, -1, 0)) count++;
if (getRelative(index, -1, 1)) count++;
if (getRelative(index, 0, -1)) count++;
if (getRelative(index, 0, 0)) count++;
if (getRelative(index, 0, 1)) count++;
if (getRelative(index, 1, -1)) count++;
if (getRelative(index, 1, 0)) count++;
if (getRelative(index, 1, 1)) count++;
return count;
}
public boolean getRelative(int index, int x, int y)
{
int relativeIndex = index + (WIDTH * y) + x;
return board.get(relativeIndex);
}
}
使用BitSet实现电路板
public class BitBoard implements Board
{
private BitSet board;
public BitBoard(int size)
{
board = new BitSet(size);
}
@Override
public void set(int index, boolean value)
{
if (value) board.set(index);
else board.clear(index);
}
@Override
public boolean get(int index)
{
return board.get(index);
}
@Override
public int length()
{
return board.length();
}
}
使用数组实现电路板
public class ArrayBoard implements Board
{
private boolean[] board;
public ArrayBoard(int size)
{
board = new boolean[size];
}
@Override
public void set(int index, boolean value)
{
board[index] = value;
}
@Override
public boolean get(int index)
{
boolean output = false;
if (index >= 0 && index < board.length)
output = board[index];
return output;
}
@Override
public int length()
{
return board.length;
}
}
最后,Board.java
public interface Board
{
public boolean get(int index);
public void set(int index, boolean value);
public int length();
}
答案 0 :(得分:4)
您的问题与BitSet
与boolean[]
效果无关。
在BitSetBoard
中,您length()
定义为:
class BitSetBoard {
...
@Override
public int length()
{
return board.length();
}
}
您的意思是返回board.size()
而不是board.length()
。 BitSet.length()
方法返回最高位集的索引,它 not 返回总大小。因此,你的主循环实际上并没有做任何事情,因为length()
在董事会清楚时返回0。
通过此更改(并将边界检查添加到BitSetBoard.get()
),BitSetBoard
的运行时间仅为ArrayBoard
的两倍。
答案 1 :(得分:0)
BitSet比boolean []的内存效率更高,除了非常小的尺寸以便进一步说明你可以阅读
boolean[] vs. BitSet: Which is more efficient?
BitSet uses about 1 bit per boolean value, and boolean[] uses about 1 byte per boolean value. that also the case that BitSet are more efficient